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Molecule optical oscillator strength

Although the actual form of f(w, q) is different from formula (4.27), the latter leads to reasonable results when we use it to calculate the cross sections of inelastic collisions and the ionization losses.120 As one of the reasons for using approximation (4.27), one can consider the fact that the data concerning the Bethe surfaces for molecules are very scant, while there is extensive information about the optical oscillator strengths of molecules both in the discrete and in the continuous regions of the spectrum (see Refs. 119 and 121). [Pg.292]

A similar theoretical study was undertaken for the core-hole states for the ethylene molecule [52], There are two identical carbon atoms and the molecule has D2h symmetry. The localized core-hole states have C2v symmetry and the direct product C2v Cs recovers properly the full symmetry of the system. The results for transition energies and optical oscillator strengths agree well with those available in the literature. [Pg.137]

Here En is the energy of the transition and fn is the corresponding optical oscillator strength, characterizing the relative contribution of that transition to the optical spectrum of the molecule. [Pg.526]

The vast majority of single-molecule optical experiments employ one-photon excited spontaneous fluorescence as the spectroscopic observable because of its relative simplicity and inlierently high sensitivity. Many molecules fluoresce with quantum yields near unity, and spontaneous fluorescence lifetimes for chromophores with large oscillator strengths are a few nanoseconds, implying that with a sufficiently intense excitation source a single... [Pg.2485]

When located at opposite ends (or at conjugated positions) in a molecular system, a donor and an acceptor do more than simply add up their separate effects. A cooperative phenomenon shows up, involving the entire disubstituted molecule, known as charge transfer (C.T.). Such compounds are colored (from pale yellow to red, absorption from 3,000 to 5,000 A) and show high U.V. absorption oscillator strength. "Figure 2 helps understand the enhancement of optical nonlinearity in such a system. [Pg.84]

Nesbitt and Hynes [57] have pointed out that much of the oscillator strength of the iodine molecule s optical absorption arises from the lowest few vibrational states of the ground electronic state (X). It is necessary for the iodine atoms to recombine and then relax to these low vibrational... [Pg.141]

The cross section a is a fundamental property of the molecule and as such is related to the molecular wave functions for the two states between which a transition is induced. Hence it is desirable to separate the contributions to a that arise from purely kinematic quantities such as the impact energy of the electron beam from those that depend solely on the properties of the molecule. To this end, a dimensionless quantity, the oscillator strength, is introduced in optical absorption spectroscopy, defined by the relation22... [Pg.9]

Here we assume that the x axis is directed along the momentum vector q, and Ne is the total number of electrons in the molecule (the atom). At small q we can confine ourselves to only the first two terms in the expansion exp iqxt) 1 + iqxr Owing to the orthogonality of the wavefunctions, the first term gives a zero contribution to the matrix element, and the generalized oscillator strength coincides with the usual optical one ... [Pg.288]

The importance of the vibron model lies in the fact that it is the doorway state of the optical absorption. (The two-particle states have no oscillator strength, since we cannot create vibrations in the ground state.) Indeed, the creation of vibrations is subsequent to an electronic excitation of a molecule, in the approximation where the absorbing dipole is the sum of molecular dipoles (with the appropriate phase), which is the approximation of weak intermolecular forces. [Pg.50]

The abundance of excited states produced directly can be calculated via the optical approximation (. The optical approximation states that the energy lost to a particular electronic transition of a molecule is proportional to f/e where f is the oscillator strength for that transition and e is the energy. For the state of benzene f 1.0 and e is 6.0 eV,... [Pg.18]


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