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Molar mass and molecular formulas

A hydrocarbon of empirical formula C,H, takes 349 s to effuse through a porous plug under the same conditions of temperature and pressure, it took 210. s for the same number of molecules of argon to effuse. What is the molar mass and molecular formula of the hydrocarbon ... [Pg.295]

A 7.85-g sample of a compound with the empirical formula C5H4 is dissolved in 301 g of benzene. The freezing point of the solution is 1.05°C below that of pure benzene. What are the molar mass and molecular formula of this compound ... [Pg.489]

The elemental analysis of an organic solid extracted from gum arabic (a gummy substance used in adhesive, inks, and pharmaceuticals) showed that it contained 40.0 percent C, 6.7 percent H, and 53.3 percent O. A solution of 0.650 g of the solid in 27.8 g of the solvent diphenyl gave a freezing-point depression of 1.56°C. Calculate the molar mass and molecular formula of the solid. K for diphenyl is 8.00°C/ot.)... [Pg.500]

The combustion of 3.795 mg of liquid B, which contains only C, H, and O, with excess oxygen gave 9.708 mg of CO2 and 3.969 mg of H2O. In a molar mass determination, 0.205 g of B vaporized at 1.00 atm and 200.0°C and occupied a volume of 89.8 mL. Derive the empirical formula, molar mass, and molecular formula of B and draw three plausible stmc-tures. [Pg.968]

Ethanol molecules can attract each other with strong hydrogen bonds dimethyl ether molecules cannot (why ). The surface tension of ethanol is greater than that of dimethyl ether because of stronger intermolecular forces (the hydrogen bonds). Note that ethanol and dimethyl ether have identical molar masses and molecular formulas so attractions resulting from dispersion forces will be equal. [Pg.294]

An unknown compound contains only carbon, hydrogen, and oxygen. Combustion analysis of the compound gives mass percents of 31.57% C and 5.30% H. The molar mass is determined by measuring the freezing-point depression of an aqueous solution. A freezing point of —5.20°C is recorded for a solution made by dissolving 10.56 g of the compound in 25.0 g water. Determine the empirical formula, molar mass, and molecular formula of the compound. Assume that the compound is a nonelectrolyte. [Pg.549]


See other pages where Molar mass and molecular formulas is mentioned: [Pg.297]    [Pg.327]    [Pg.346]    [Pg.347]    [Pg.361]    [Pg.863]    [Pg.422]    [Pg.536]    [Pg.882]    [Pg.1054]    [Pg.850]    [Pg.422]    [Pg.387]    [Pg.450]    [Pg.423]    [Pg.574]    [Pg.523]   
See also in sourсe #XX -- [ Pg.198 ]




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Formula mass

Formulas molecular formula

Molar mass

Molarity molar masses

Molecular and Formula Masses

Molecular formula

Molecular mass

Molecular molar mass

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