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Layer displacement

A simple derivation of tliis equation based on tire lowest-order derivative (curvature) of tire layer displacement field u(r) has been provided [87]. A similar expression can be obtained for a uniaxial columnar phase [20] (witli tire columns lying in tire z direction) ... [Pg.2558]

More sophisticated rotors can be loaded with gradient and sample while rotating. When the batch is finished or the bands are sufficientiy loaded with material, the bowl may be stopped slowly and the reoriented layers displaced under static conditions. Rotors may also be designed to estabUsh gradients and isopycnic bands of sample and then be unloaded dynamically by introducing a dense solution near the edge of the rotor as shown in Figure 12. [Pg.408]

A number of theories have been put forth to explain the mechanism of polytype formation (30—36), such as the generation of steps by screw dislocations on single-crystal surfaces that could account for the large number of polytypes formed (30,35,36). The growth of crystals via the vapor phase is beheved to occur by surface nucleation and ledge movement by face specific reactions (37). The soHd-state transformation from one polytype to another is beheved to occur by a layer-displacement mechanism (38) caused by nucleation and expansion of stacking faults in close-packed double layers of Si and C. [Pg.464]

Ordinary hexagonal graphite has a structure that repeats the ABAB. .. alternation of layers rhombohedral graphite has the repetition ABCABC. . ., with the C layer displaced from the other two. Sketch a structure for rhombohedral graphite. [Pg.740]

Leadbetter AJ, Norris EK (1979) Molec Phys 38 669. There are different contributions which give rise to a broadening a of the molecular centre of mass distribution function f(z). The most important are the long-wave layer displacement thermal fluctuations and the individual motions of molecules having a random diffusive nature. The layer displacement amplitude depends on the magnitude of the elastic constants of smectics ... [Pg.237]

Preparation of Phosphorus Trichloride and Pentachloride. This experiment is performed by two students in a fume cupboard Assemble an apparatus as shown in Fig. 96. Put 0.2 g of dry red phosphorus into each of Wurtz test tubes 1 and 2. See that the lower ends of gas-discharge tubes 3 feeding chlorine into reaction tubes 1 and 2 are 2-3 cm above the phosphorus layer. Displace air from the apparatus using dry carbon dioxide gas, and then fill it with dry chlorine... [Pg.153]

In the framework of irreversible thermodynamics (compare, for example, [31, 32]) the macroscopic variables of a system can be divided into those due to conservation laws (here mass density p, momentum density g = pv with the velocity field v and energy density e) and those reflecting a spontaneously broken continuous symmetry (here the layer displacement u characterizes the broken translational symmetry parallel to the layer normal). For a smectic A liquid crystal the director h of the underlying nematic order is assumed to be parallel to the layer normal p. So far, only in the vicinity of a nematic-smectic A phase transition has a finite angle between h and p been shown to be of physical interest [33],... [Pg.103]

Throughout this chapter we focus on the extended hydrodynamic description for smectic A-type systems presented in [42,43], We discuss the possibility of an undulation instability of the layers under shear flow keeping the layer thickness and the total number of layers constant. In contrast to previous approaches, Auernhammer et al. derived the set of macroscopic dynamic equations within the framework of irreversible thermodynamics (which allows the inclusion of dissipative as well as reversible effects) and performed a linear stability analysis of these equations. The key point in this model is to take into account both the layer displacement u and the director field ft. The director ft is coupled elastically to the layer normal p = in such a way that ft and p are parallel in equilibrium z is the coordinate perpendicular to the plates. [Pg.104]

Let us briefly review the essential ingredients to this procedure (for more details of the method see [30] and for our model [42]). For a given system the hydrodynamic variables can be split up into two categories variables reflecting conserved quantities (e.g., the linear momentum density, the mass density, etc.) and variables due to spontaneously broken continuous symmetries (e.g., the nematic director or the layer displacements of the smectic layers). Additionally, in some cases non-hydrodynamic variables (e.g., the strength of the order parameter [48]) can show slow dynamics which can be described within this framework (see, e.g., [30,47]). [Pg.107]

Qij = jS (rnrij - j5y)] and the layer displacement u and the modulus in the smectic A case [cp = S(s> exp ir/o(z - n) ]. Here, as in the rest of the chapter, we refer to the system of coordinates defined in Sect. 2.1. We note that u is only a good variable if we consider small deformations of the layers. For large layer deformations the phase

further discussion, we will concentrate on the parts due to symmetry variables and the order parameters, while for terms already present in the isotropic fluid see, e.g., [30, 31]. [Pg.108]

Furthermore, there is a reversible coupling between the layer displacement and the velocity field in (16). But its coupling constant has to be unity due to the Gallilei invariance of the equations. As mentioned above, the use of u is limited to small layer deformations. [Pg.112]

To solve these equations we need suitable boundary conditions. In the following we will assume that the boundaries have no orienting effect on the director (the homeotropic alignment of the director is only due to the layering and the coupling between the layer normal p and the director h). Any variation of the layer displacement must vanish at the boundaries ... [Pg.113]

We write the solution as the vector X = (6,(j),u,vx,vy,i ,P,) consisting of the angular variables of the director, the layer displacement, the velocity field, the pressure, and the modulus of the (nematic or smectic) order parameter. For a spatially homogeneous situation the equations simplify significantly and the desired solution Xo can directly be found (see Sect. 3.1). To determine the region of stability of Xq we perform a linear stability analysis, i.e., we add a small perturbation Xi to... [Pg.113]

The modulations of S in the linear analysis are maximum at the boundaries and in phase with the layer displacement u. The sign of the amplitude depends on the coupling to the velocity field (only the anisotropic part — /) [< is relevant) and on the coupling to the director undulations (via M , only for the nematic... [Pg.124]

The strategy is as follows. We start by rewriting the equations in cylindrical coordinates (r, ,z). The variables we consider are the layer displacement u (now in the radial direction) from the cylindrical state, the director n, and the fluid velocity v. The central part of the cylinder, r < Ri, containing a line defect, is not included. It is not expected to be relevant for the shear-induced instability. We write down linearized equations for layer displacement, director, and velocity perturbations for a multilamellar (smectic) cylinder oriented in the flow direction (z axis). We are interested in perturbations with the wave vector in the z direction as this is the relevant direction for the hypothetical break-up of the cylinder into onions. The unperturbed configuration in the presence of shear flow (the ground state) depends on r and 0 and is determined numerically. The perturbations, of course, depend on all three coordinates. We take into account translational symmetry of the ground state in the z direction and use a plane wave ansatz in that direction. Thus, our ansatze for the perturbed variables are... [Pg.132]

Fig. 19 Second order in YYi /B effects the ground state layer displacement (°) and at r = 0.751 as functions of the polar angle 0. Note the quadrupolar deformation of the cylinder... Fig. 19 Second order in YYi /B effects the ground state layer displacement (°) and at r = 0.751 as functions of the polar angle 0. Note the quadrupolar deformation of the cylinder...
Fig. 21 The shear plane cross section of the layer displacement uW (exaggerated) and the corresponding velocity perturbation v,( 11... Fig. 21 The shear plane cross section of the layer displacement uW (exaggerated) and the corresponding velocity perturbation v,( 11...
In our earlier work [42] we considered two independent variables the layer displacement and the y-component of the director. To compare our present analysis to these results we expand (43) and (44) in power series in do (up to 6q) and take only the terms connected with 0 and u ... [Pg.141]

Most chemical reactions are in fact accompanied by the occurrence of stress due to (/) the difference in the coefficients of thermal expansion of the phases involved into the interaction and (ii) the volume effect associated with the formation of a chemical compound, the volume of the reactants consumed being in general not equal to the volume of the product(s) formed. As the stresses arisen at both layer interfaces are different, the layer displacement relative to the initial interface depends also on their magnitudes. [Pg.25]

This equation relates the gradient of the velocity in the core region to the rate of growth of the boundary layer displacement thickness. [Pg.331]

Consistent with LEED results (above) MEIS/10/ for layer displacements and lateral motions. [Pg.151]

Table 4 Surface relaxations in the outermost atomic layers of the (111) surface (for M on top of O, site), reported for two different metal coverages 6= and 0.25 ML, Surface displacements are calculated as the difference of the ideal (111) surface and the relaxed geometry of the Pd and Pt/Zr02 interfaces. Negative and positive values indicates inwardly and outwardly displacements, respectively. For 0=0.25 ML, O., denotes the surface ion to which an metal atom is bound, while Oj represent the non-bound surface oxygens equivalent notation for the other surface layers. Displacements are given in A. Table 4 Surface relaxations in the outermost atomic layers of the (111) surface (for M on top of O, site), reported for two different metal coverages 6= and 0.25 ML, Surface displacements are calculated as the difference of the ideal (111) surface and the relaxed geometry of the Pd and Pt/Zr02 interfaces. Negative and positive values indicates inwardly and outwardly displacements, respectively. For 0=0.25 ML, O., denotes the surface ion to which an metal atom is bound, while Oj represent the non-bound surface oxygens equivalent notation for the other surface layers. Displacements are given in A.

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See also in sourсe #XX -- [ Pg.43 ]

See also in sourсe #XX -- [ Pg.220 , Pg.224 , Pg.234 , Pg.303 ]




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