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Laws Kelvin equation

Of course, V = mT is another way to write Charles s Law. The equation of the line using the Celsius data has the form V = mT + b. That is, there is a nonzero y-intercept. If the line does not go through the origin, then Charles s Law would have to include a term to correct for the nonzero value of the y-intercept (b). Of course, this is doable, but it is not as convenient. To avoid this hassle, we always use the kelvin temperature. [Pg.132]

Combining (9.21) with the Kelvin equation (9.18) and using Darcy s law for liquid flow through porous media (as similarly done before for gas flow, see Eq. (9.1)) yields an expression for the gas flux Jd3 of capillary condensate in case 3 of Fig. 9.9 ... [Pg.352]

Derivation of the Kohler equation is based on a combination of two expressions the Kelvin equation, which governs the increase in water vapor pressure over a curved surface and modified Raoult s law, which describes the water equilibrium over a flat solution ... [Pg.812]

Ideal gas law an equation relating the properties of an ideal gas, expressed as PV = nRT, where P = pressure, V = volume, n = moles of the gas, R = the universal gas constant, and T = temperature on the Kelvin scale. This equation expresses behavior closely approached by real gases at high temperature and/or low pressure. [Pg.830]

The aim of this book is to show that there is a great deal of science in ice cream, and in particular to demonstrate the link between the microscopic structure and the macroscopic properties. It is naturally biased towards physics, physical chemistry and materials science as these are the areas in which I trained. The book is aimed at schools and universities, and a scientific background is required to understand the more technical sections. I have attempted to make it readable by 16-18-year-olds, and many sections are suitable for adaptation by GCSE science teachers. I have unashamedly made reference to the giants of chemistry and physics such as Newton, Einstein, Boyle, Gibbs, Kelvin, Laplace and Young where the laws and equations that bear their names are relevant. I hope that as a result teachers reading this book will find in ice cream useful illustrations of a number of scientific principles. Some... [Pg.197]

For a macroscopicly large slit of width L, capillary condensation is a first-order transition. The shift of the liquid-vapor coexistence curve P = Pi/l(.T) in the capillary relative to the bulk pressure P = Po(T ) is described by the Kelvin equation 8P = Po(T ) — i/t(f) 1/L. In the case of capped capillaries with a finite depth D and width L, capillary condensation becomes a continuous phase transition. There is a power law with corresponding critical exponents characterizing the unbinding of the meniscus from the bottom of the capped capillary if the pressure P approaches the... [Pg.112]

Note that this Four-Parameter Fluid model is composed of a Kelvin element (subscripts 1) and a Maxwell element (subscripts 0). Thus, the constitutive laws (differential equations) for the Kelvin and Maxwell elements need to be used in conjunction with the kinematic and equilibrium constraints of the system to provide the governing differential equation. Again, treating the time derivatives as differential operators will allow the simplest derivation of Eq. 5.12. The derivation is left as an exercise for the reader as well as the determination of the relations between the pi and q, coefficients and the spring moduli and damper viscosities (see problem 5.1). [Pg.164]

In the process represented by equation (4.23), the temperature changes from T to T". What we must investigate is the possibility that T" can equal 0 Kelvin. The Second Law predicts that for this process... [Pg.188]

Figure 10.14a shows such a plot for Kr.10 The straight line below 7 2 = 4 K2 (Ts= 2 K) demonstrates the validity of equation (10.160). A graph similar to the one shown in Figure 10.14a was used in Chapter 4 to extrapolate Cr resultsgg to zero Kelvin when we used the Third Law to obtain absolute entropies. [Pg.577]

Write an equation for the combined gas law using temperature in Celsius. Explain why the Kelvin scale is more convenient. [Pg.201]

Furthermore, in the four steps of the cycle (Fig. 6.8) three are adiabatic (one irreversible, two reversible). Hence, Qcycie is identical with Q of the isothermal step, that is, Q of Equation (6.104). If g > 0, then W < 0 that is, work would have been performed by the system. In other words, if Q were positive, we would have carried out a cyclical process in which heat at a constant temperature had been converted completely into work. According to the Kelvin-Planck statement of the second law, such a process cannot be carried out. Hence, Q cannot be a positive number. As Q must be either negative or zero, it follows from Equation (6.104) that... [Pg.140]

An interesting alternative demonstration of Equation (7.75) can be carried out on the basis of isothermal cycles and of the Kelvin-Planck statement of the second law. Consider two possible methods of going from State a to State b, a spontaneous change of state, in an isothermal fashion (Fig. 7.1) (1) a reversible process and (2) an irreversible process. [Pg.176]

This relationship for Newtonian viscosity is valid normally for temperatures higher than 50 °C or more above the Tg. The utility of the Arrhenius correlation can be limited to a relatively small temperature range for accurate predictions. The viscosity is usually described in this exponential function form in terms of an activation energy, Af, absolute temperature T in Kelvin, the reference temperature in Kelvin, the viscosity at the reference T, and the gas law constant Rg. As the temperature approaches Tg for PS (Tg = 100°C), which could be as high as 150°C, the viscosity becomes more temperature sensitive and is often described by the WLF equation [10] ... [Pg.102]

In this equation, R is called the ideal gas law constant. Its value depends on the units used, but assuming pressure is measured in atmospheres, volume in liters, and temperature in Kelvins its value is 0.082 atm-L/mol-K. Other forms of the ideal gas law are... [Pg.107]

This problem asks for a value of n when V, P, and T are given. Rearrange the ideal gas law to the form n = PV/RT, convert the temperature from degrees Celsius to Kelvin, and substitute the given values of P, V, and T into the equation. [Pg.351]


See other pages where Laws Kelvin equation is mentioned: [Pg.79]    [Pg.694]    [Pg.500]    [Pg.411]    [Pg.216]    [Pg.425]    [Pg.361]    [Pg.17]    [Pg.383]    [Pg.272]    [Pg.349]    [Pg.401]    [Pg.326]    [Pg.63]    [Pg.580]    [Pg.662]    [Pg.265]    [Pg.91]    [Pg.244]    [Pg.401]    [Pg.231]    [Pg.349]    [Pg.728]    [Pg.736]    [Pg.200]    [Pg.219]   
See also in sourсe #XX -- [ Pg.279 , Pg.407 ]




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Equation Kelvin

KELVINS LAW

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