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K- plane

In order to establish conditions for the isolation of the image of point D under the EM map, the projection is performed by first taking a section through the surface ct = 0 at fixed J, an example of which is shown in the right-hand panel of Fig. 15, for the critical value = S — N. The shaded area of the (K, plane defines the classically allowed range for the specified value. The lines indicate energy contours for y = 0.5. Those that touch the section correspond to relative equilibria of the Hamiltonian, whose values... [Pg.68]

This expression is used in all cases where atom i is connected to exactly three other atoms, /. k and l. Here, Kiju is the force constant, ( ijki is the angle between the i-l axis and the i-j-k plane and the expansion coefficients depend on the central atom type ... [Pg.39]

An alternative way of portraying the pattern formation behaviour in systems of the sort under consideration here is to delineate the regions in chemical parameter space (the h k plane) over which the uniform state is unstable to non-uniform perturbations. We have already seen in chapter 4, and in Fig. 10.3, that we can locate the boundary of Hopf instability (where the uniform state is unstable to a uniform perturbation and at which spatially uniform time-dependent oscillations set in). We can use the equations derived in 10.3.2 to draw similar loci for instability to spatial pattern formation. For this, we can choose a value for the ratio of the diffusivities / and then find the conditions where eqn (10.48), regarded as a quadratic in either y or n, has two real positive solutions. The latter requires that... [Pg.277]

Fig. 10.14. Representation of region for stable spatial stationary state in the n-K plane for a system with n = 0.05. The left-hand ordinate gives the general locus for any y, the right-hand ordinate is appropriate to the specific case y = 167t2. Fig. 10.14. Representation of region for stable spatial stationary state in the n-K plane for a system with n = 0.05. The left-hand ordinate gives the general locus for any y, the right-hand ordinate is appropriate to the specific case y = 167t2.
The dispersion relation det(J) = 0 can also be viewed in the n-K plane, as in Fig. 10.14. This allows us to read off the maximum value of the dimensionless rate constant for which a given mode can be found. The left-hand ordinate corresponds to general values of the group nn/y112, the right-hand ordinate to our specific example y = 6n2. Thus, for the latter case, a pattern with n = 5 requires 0.01 < k < 0.0148. [Pg.289]

More generally the following question may be asked. When the values of x are confined to a certain subset / of the real axis, how does this show up in the properties of G If / is the interval — a < x < a it is known that G(k) is analytic in the whole complex k-plane and of exponential type . If I is the semi-axis x 0 the function G(k) is analytic and bounded in the upper half-plane. But no complete answer to the general question is available, although it is important for several problems. [Pg.8]

Call a two-faced map and, specifically, ( a, b), k)-map any valent map with only a- and fc-gonal faces, for given integers 2 < a < b. We will also use terms ( a, b], k) sphere (moreover, ( a, b], k)-polyhedron if it is 3-connected) or ( a, b), k)-torus for maps on sphere S2 or torus K2, respectively. Call ( a, b], k)-plane any infinite /c-valent plane graph with a- and fe-gonal faces and without exterior faces. More generally, for R c N — 1, call (R,k)-map a k-valent map whose faces have gonalities i 6 R. [Pg.24]

The geometrical features of shear deformation are shown in Fig. 24.5. Here, the shear is on the K plane in the direction of d. The initial unit sphere is deformed into an ellipsoid and the Ki plane is an invariant plane. The K2 plane is rotated by the shear into the K 2 position and remains undistorted. A reasonable slip system to assume for the lattice-invariant shear deformation is slip in a (111) direction on a 112 plane in the b.c.t. lattice, which corresponds to slip in a (110) direction on a 110 plane in the f.c.c. lattice. [Pg.568]

In addition to looking at the position of the eigenvalues in the k-plane, we can also analyze their appearance on the complex energy plane due to the direct connection between the energy of the particle and its momentum at the asymptotes E = y. Figure 1.9 shows the distribution of the Siegert solutions on both the Energy and the wave vector (k) planes. [Pg.18]

We consider the analytic continuation of the S(k) matrix into the complex k plane. Then, the phase shift is complex in general and the absolute value of... [Pg.175]

A number of closely lying resonances in multichannel scattering is a difficult problem to treat theoretically. Even the representation of the S matrix is very complex for these overlapping resonances as compared with the Breit-Wigner one-level formula. Various alternative proposals are found in the literature, as is reviewed by Belozerova and Henner [61]. This is mainly due to the formidable task of constructing an explicitly unitary and symmetric S matrix having more than one pole when analytically continued into the complex k plane. Thus, possible practical forms of the S matrix for overlapping resonances may be explicitly symmetric and implicitly unitary, or explicitly unitary and implicitly symmetric. [Pg.194]

This completes the definition of the stability problem for the mixed convection flow over the horizontal plate. For a given K and Re, one would be required to solve (6.4.19)-(6.4.38), starting with the initial conditions (6.4.39)-(6.4.58) and satisfy (6.4.63) for particular combinations of the eigenvalues obtained as the complex k and u>. We will use the procedure adopted in Sengupta et al. (1994) to obtain the eigen-spectrum for the mixed convection case, when the problem is in spatial analysis framework. In the process, it is possible to scan for all the eigenvalues in a limited part of the complex k- plane, without any problem of spurious eigenvalues. [Pg.209]

Figure 6.2 Zero-contour lines of Dr and Di shown plotted in a limited region of the complex wave number plane for the case of Re = 1000, K = 1.0 X 10 and ujq = 0.1. The eigenvalues are marked as indicated in Table 6.2. (b) Complex k- plane showing all the branch point with coordinates as indicated in the box. Figure 6.2 Zero-contour lines of Dr and Di shown plotted in a limited region of the complex wave number plane for the case of Re = 1000, K = 1.0 X 10 and ujq = 0.1. The eigenvalues are marked as indicated in Table 6.2. (b) Complex k- plane showing all the branch point with coordinates as indicated in the box.
According to the residue theorem applied to the k" integral the scattering is determined by the poles of the partial T-matrix element in the complex k" plane. The existence and positions of the poles are of course determined by the details of the potential V, but we will assume that there is a pole corresponding to complex energy Cr — iTr. The magnitude of the partial T-matrix element varies rapidly with values of E near the pole and we can consider er as the resonance energy. For the cross section we need only consider the on-shell partial T-matrix element... [Pg.105]

If the metal catalyst particles were present only in the form of these idealized crystals, then the number of active comer atoms present would be very low. However, STO evaluations of dispersed metal catalysts have shown that these active atoms are present in rather large amounts, at times as high as 30%-35% of the total metal atoms present. Such high surface concentrations of the highly unsaturated atoms can only be accounted for by the presence of the irregular particle shapes that were observed using dark field TEM imaging techniques. Additional active sites are probably present as adatoms on the 111 (M) and 100 (K) planes as shown in Fig. 4.4. [Pg.56]

In order to obtain the stability diagram for the three-body Coulomb systems in the X — K)-plane, one has to calculate the transition line, Xc(k), which separates the stable phase from the unstable one. To carry out the finite-size scaling calculations, the following complete basis set was used [66] ... [Pg.51]

Uniaxial (birefrigerent) crystals have an index of refraction that depends on the projection of the oscillating electric field of linearly polarized radiation on the unique axis (the optic axis) of the crystal. Consider the plane defined by the optic axis of the uniaxial crystal, c, and the propagation direction of the oq beam, which is described by the unit vector, k = k uji)/ k(ui ). Light polarized perpendicular to the c,k plane is called the ordinary ray and propagates according to the ordinary index of refraction,... [Pg.50]

Light polarized in the c, k plane propagates with an index of refraction that is dependent on the projection of the polarization direction on c... [Pg.50]

The comparison of the different behavioural domains in parameter space shows that simple periodic oscillations remain, by far, the most common type of dynamic behaviour. Complex periodic oscillations of the bursting type are also rather frequent, but much less than simple oscillations. The coexistence between a steady state and a limit cycle comes third by virtue of the importance of the domain in which such behaviour occurs in the v-k plane. Birhythmicity and chaos come next... [Pg.157]

To account for the transitions no relay relay oscillations, it is desirable that the system, in the a - k plane, follow the path marked by an arrow. This trajectory, starting in A from a nonexcitable state characterized by a low level of cAMP, would enter the excitable domain B, where relay would occur, before moving into domain C where cAMP oscillations would begin spontaneously. Finally, the passage to a domain located to the left of region C would bring an end to the oscillations by leading the system into a stable state characterized by an elevated level of cAMP. [Pg.286]

The above equation proves that p is identical to P-n and cannot be negative. On the other hand, it follows from Eqs. (10,12, and 14) fhat the complex solutions are seated on the lower half of the k plane distributed symmetrically with respect to the imaginary fc-axis. For a = 0 one may have solutions along positive and negative values on the imaginary k-axis. [Pg.412]

One sees from Eq. (26) that the residue is proportional to the resonant functions Un r) and M (r )- The factors 2mlh and 2/< , that appear respectively, in the numerator and denominator, are there because the derivation was made in the k plane. As shown by Eq. (A.16) these factors are absent if the derivation performed in the complex energy plane. [Pg.415]


See other pages where K- plane is mentioned: [Pg.439]    [Pg.170]    [Pg.37]    [Pg.255]    [Pg.281]    [Pg.316]    [Pg.144]    [Pg.146]    [Pg.147]    [Pg.57]    [Pg.207]    [Pg.350]    [Pg.19]    [Pg.51]    [Pg.31]    [Pg.307]    [Pg.212]    [Pg.216]    [Pg.471]    [Pg.302]    [Pg.52]    [Pg.285]    [Pg.53]    [Pg.160]    [Pg.339]    [Pg.263]    [Pg.50]    [Pg.170]    [Pg.414]   
See also in sourсe #XX -- [ Pg.70 ]




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Estimation of Markers Distributions Near the Virtual K-Plane

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