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Hydrogen fluoride molecules, bonding

The experimental bond length for the hydrogen fluoride molecule is 0.917A. Determine the basis set required to predict this structure accurately. Perform your optimizations at the MP4 level of theory (electron correlation is known to be important for this system). [Pg.103]

The fluorination of 2,5-dihydroxybenzo-l,4-quinone and 2-hydroxynaphtho-l,4-quinone results, as well as replacement of the carbonyl oxygen atoms by fluorines, in replacement of the hydroxy groups and addition of a hydrogen fluoride molecule across a C = C bond to give,... [Pg.347]

Show how a hydrogen Is atomic orbital and a fluorine 2p atomic orbital overlap to form bonding and antibonding MOs in the hydrogen fluoride molecule. Are they cr or 77 MOs ... [Pg.698]

In this molecule, the hydrogen fluoride molecule, there is a single covalent bond (shared-electron-pair bond), which holds the hydrogen atom and the fluorine atom firmly together. The distance between the nuclei of these two atoms is 0.92A, according to experimental determination made by the study of the spectrum of the gas. [Pg.235]

In discussing bonds involving hybrid AO s it is necessary to introduce atomic valence states. If the above description (p. 96) is accepted, the energy of the hydrogen fluoride molecule can be discussed. The bond is... [Pg.97]

Figure 29.3. The hydrogen fluoride molecule dependence of overlap on orbital symmetry, a) Overlap of lobes of same phase leads to bonding. b) Positive overlap and negative overlap cancel each other. Figure 29.3. The hydrogen fluoride molecule dependence of overlap on orbital symmetry, a) Overlap of lobes of same phase leads to bonding. b) Positive overlap and negative overlap cancel each other.
The hydrogen fluoride molecule may be used as a simple example of this approach. Using the 6-31G basis the PA charge on F is -0.395 e. This monopole value yields, when combined with the bond distance of 1.733 au, a dipole moment of 0.685. However, the exact operator dipole obtained from the wavefunction is 0.776. In the cumulative procedure, the difference between these two values is made up with atomic dipoles. From [13] one obtains (w)f = + 0.330 and [w] = +0.446, which of course sum to the exact molecular dipole. Application of Eq. [14] yields cumulative atomic dipoles Mj. = -0.012 and Mh = 0.103. The sum of the PA charge dipole plus the atomic dipoles equals the exact molecular dipole. Analogous procedures are used for higher moments. [Pg.234]

The procedure of taking a linear combination of atomic orbitals, which we have considered with respect to the H2 molecule, is very fruitful when applied to other covalent bonds. Consider, for example, the hydrogen fluoride molecule, HF, formed from a hydrogen atom with one electron in the Is state and a fluorine atom with an electron configuration of ls 2s 2p. Fluorine has an unpaired 2p electron, and we can form a wave function of the Heitler-London type by making use of the atomic orbitals for this 2p electron and for the Is electron in the hydrogen atom ... [Pg.30]

Desaibe the type of chemical bonding that exists between the atoms in the hydrogen fluoride molecule, HR... [Pg.435]

In this molecule, the hydrogen fluoride molecule, there is a single covalent bond that holds the hydrogen atom and the fluorine atom firmly together. [Pg.145]

The hydrogen fluoride molecule (A) and the hydrogen difluoride ion, containing a hydrogen bond (B). [Pg.287]


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See also in sourсe #XX -- [ Pg.285 ]




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