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Freezing equation

It is also important to imderstand the difference between the lowering of the melting temperature predicted by Equation 11.9 and that predicted by the Clapeyron equation (Equation 11.6). The Clapeyron equation applies when both the solid and the liquid phase are under the same pressure. It predicts a raising of the freezing temperature with pressure of a substance such as a metal that contracts when it freezes. Equation 11.9 applies when only the solid is subjected to pressure such as occurs at the point of contact between... [Pg.215]

One practical application is determining if freezeout may be occurring or not. This is indicated by the prevailing value of the temperature ratio, ATr. Equation 6 is used to calculate the temperature ratio at its value that the freezeout layer is exactly zero, or the division between freezing and not freezing. Equation 6 is equated to zero and solved for the temperature ratio to give... [Pg.3054]

For example, the SHAKE algorithm [17] freezes out particular motions, such as bond stretching, using holonomic constraints. One of the differences between SHAKE and the present approach is that in SHAKE we have to know in advance the identity of the fast modes. No such restriction is imposed in the present investigation. Another related algorithm is the Backward Euler approach [18], in which a Langevin equation is solved and the slow modes are constantly cooled down. However, the Backward Euler scheme employs an initial value solver of the differential equation and therefore the increase in step size is limited. [Pg.272]

The ultimate distribution represents the maximum separation that can be attained without cropping the ingot. Equation (22-5) is approximate because it does not include the effect of progressive freezing in the last zone length. [Pg.1992]

This equation may also be used to calculate the wall thickness distribution in deep truncated cone shapes but note that its derivation is only valid up to the point when the spherical bubble touches the centre of the base. Thereafter the analysis involves a volume balance with freezing-off on the base and sides of the cone. [Pg.312]

This equation cannot be integrated as simply as before because h is now a function of time. Fig. 5.26 shows how the depth of the cavity changes with time as the melt flows. Barrie has investigated this situation and concluded that the freezing-off could be described by a relation of the form... [Pg.397]

However, in the non-isothermal case the pressure is also high at low injection rates. This is because slow injection gives time for significant solidification of the melt and this leads to high pressures. It is clear therefore that in the non-isothermal case there is an optimum injection rate to give minimum pressure. In Fig. 5.28 this is seen to be about 3.0 x 10 m /s for the situation considered here. This will of course change with melt temperature and mould temperature since these affect the freeze-off time, //, in the above equations. [Pg.404]

To be specific, we consider the two-dimensional growth of a pure substance from its undercooled melt in about its simplest form, where the growth is controlled by the diffusion of the latent heat of freezing. It obeys the diffusion equation and appropriate boundary conditions [95]... [Pg.889]

In this equation, Pt is the vapor pressure of solvent over the solution, P° is the vapor pressure of the pure solvent at the same temperature, and Xj is the mole fraction of solvent. Note that because Xj in a solution must be less than 1, P must be less than P°. This relationship is called Raoult s law Francois Raoult (1830-1901) carried out a large number of careful experiments on vapor pressures and freezing point lowering. [Pg.268]

Boiling point elevation and freezing point lowering, like vapor pressure lowerings are colligative properties. They are directly proportional to solute concentration, generally expressed as molality, m. The relevant equations are... [Pg.269]

The proportionality constants in these equations, fcb and kf, are called the moled boiling point constant and the moled freezing point constant, respectively. Their magnitudes depend on the nature of the solvent (Table 10.2). Note that when the solvent is water,... [Pg.269]

Strategy First (1) calculate the number of moles of C2H602 (MM = 62.07 g/mol). Then (2) apply the defining equation to calculate the molality. Finally (3), use the equation ATf = (1.86°C/m) X molality to find the freezing point lowering. [Pg.270]

Reality Check Actually, the freezing point is somewhat lower, about — 37°C (—35°F), which reminds us that the equation used, ATf = kftn, is a limiting law, strictly valid only in very dilute solution. [Pg.270]

To calculate the freezing point lowering of an electrolyte in water, we use the general equation... [Pg.275]

The freezing point of a 0.50 m solution of oxalic add, H2C2O4, in water is — 1.12°C. Which of the following equations best represents what happens when oxalic acid dissolves in water ... [Pg.277]

The ionisation may be attributed to the great tendency of the free hydrogen ions H+ to combine with water molecules to form hydroxonium ions. Hydrochloric and nitric acids are almost completely dissociated in aqueous solution in accordance with the above equations this is readily demonstrated by freezing-point measurements and by other methods. [Pg.20]

The equations for the vapour pressures and freezing-points of dilute solutions are also readily deduced from Planck s equation. [Pg.374]

J. B. Goebel (Zeitschr. physik. Chem., 53, 213, 1905 54, 314, 1906 71, 652, 1910) has found an empirical equation for the depression of freezing-point in aqueous solutions of total molecular concentration n ... [Pg.374]

According as we put dT, dp, or ds equal to zero, we have the equations representing the alteration of pressure required to keep a solution of altered concentration in equilibrium with ice at the same temperature, or the alteration of freezing-point with concentration, or the alteration of freezing-point of a given solution with pressure, respectively. Similar equations apply when the solid is the pure solid solute, e.g., a salt along with its saturated solution. [Pg.418]

If we take Dieterici s numbers for the vapour pressures, and Roloff s for the freezing-points, of solutions of potassium chloride, we can calculate the osmotic pressure (P0) from the two equations ... [Pg.422]

Range of a process, 114 Rankine s cycle, 113 vapour-pressure equation, 179 Raoult s freezing-point law, 299 ... [Pg.542]

Van t Hoff s boiling-point equation, 295 freezing-point equation, 299 theory of solution, 287 principle of mobile equilibrium, 304, 340... [Pg.543]

Freezing point methods are often applied to the measurement of activities of electrolytes in dilute aqueous solution because the freezing point lowering, 6= T — T, can be determined with high accuracy, and the solute does not dissolve in the solid to any appreciable extent. Equations can be derivedgg relating a to 9 instead of T and T. The detailed expressions can be found in the literature.16... [Pg.309]

Equation (8.26) relates the melting temperature, T, of an ideal solution to the mole fraction,, v of the (pure) component that freezes from solution. It can be integrated by separating variables and setting the integration limits between T, the melting temperature where the mole fraction is. y, and 7, the melting temperature of the pure component, /, where. v, = 1. The result is... [Pg.419]

Decomposition of BeS04 (either reagent grade or freeze-dried) yielded BeO [771] and kinetic analyses based on the contracting area equation [eqn. (7), n = 2] for 875—990 K gave values of E from 213 to 226 kJ mole-1. Under non-isothermal conditions, the values of E varied between... [Pg.175]


See other pages where Freezing equation is mentioned: [Pg.682]    [Pg.407]    [Pg.526]    [Pg.526]    [Pg.527]    [Pg.446]    [Pg.449]    [Pg.450]    [Pg.450]    [Pg.554]    [Pg.140]    [Pg.385]    [Pg.1127]    [Pg.348]    [Pg.373]    [Pg.419]    [Pg.540]    [Pg.84]    [Pg.308]    [Pg.418]    [Pg.420]    [Pg.421]    [Pg.655]   
See also in sourсe #XX -- [ Pg.123 ]




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