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Calculations Based on Net Ionic Equations

The net ionic equation (Chap. 9), like all balanced chemical equations, gives the ratio of moles of each substance to moles of each of the others. It does not immediately yield information about the mass of the entire salt, however. (One cannot weight out only Ba + ions.) Therefore, when masses of reactants are required, the specific compound used must be included in the calculation. [Pg.147]

EXAMPLE 10.12. (a) How many moles of silver ion are required to make 5.00 g AgCl (b) What mass of silver nitrate is required to prepare 5.00 g AgCl  [Pg.147]

from the balanced chemical equation, 0.0350 mol of Ag is required  [Pg.147]

when treated with enough chloride ion, 5.95 g of AgNOj will produce 5.00 g of AgCl. [Pg.147]

EXAMPLE 10.13. What is the maximum mass of BaS04 that can be produced when a solution containing 4.35 g of Na2S04 is added to another solntion containing an excess of Ba +  [Pg.147]


Inst as compounds have definite ratios of elements, chemical reactions have definite ratios of reactants and products. Those ratios are used in Section 10.1 to calcnlate the number of moles of other substances in a reaction from the nnm-ber of moles of any one of the snbstances. Section 10.2 combines information from Section 10.1, Chapter 7, and elsewhere to explain how to calcnlate the mass of any substance involved in a reaction from the mass of another. Section 10.3 demonstrates how to work with qnantities in nnits other than moles or masses when finding quantities of reactants or prodncts. Section 10.4 shows how to calcnlate the quantities of snbstances involved in a reaction even if the quantities of reactants present are not in the mole ratio of the balanced equation. Section 10.5 covers the calculation of the percentage yield of a product from the actual yield and the theoretical yield, based on the amonnt(s) of reactant(s). Section 10.6 explains which of these types of calcnlations can and cannot be done with net ionic equations. [Pg.269]

The basic derivations of the van der Waals forces is based on isolated atoms and molecules. However, in many particle calculations or in the condensed state major difficulties arise in calculating the net potential over all possible interactions. The Debye interaction, for example is non additive so that a simple integration of Equation (4.27) over all units will not provide the total dipole-induced dipole interaction. A similar problem is encountered with the dipole-dipole interactions which depend not only on the simple electrostatic interaction analysis, but must include the relative spatial orientation of each interacting pair of dipoles. Additionally, in the condensed state, the calculation must include an average of all rotational motion. In simple electrolyte solutions, the (approximately) symmetric point charge ionic interactions can be handled in terms of a dielectric. The problem of van der Waals forces can, in principle, be approached similarly, however, the mathematical complexity of a complete analysis makes the Keesom force, like the Debye interaction, effectively nonadditive. [Pg.69]


See other pages where Calculations Based on Net Ionic Equations is mentioned: [Pg.155]    [Pg.160]    [Pg.147]    [Pg.156]    [Pg.66]    [Pg.69]    [Pg.155]    [Pg.160]    [Pg.147]    [Pg.156]    [Pg.66]    [Pg.69]    [Pg.196]    [Pg.106]    [Pg.54]   


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