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Based on Chemical Equations

We are now ready to use chemical equations to calculate the relative amounts of substances involved in chemical reactions. Let us again consider the combustion of methane in oxygen. The balanced chemical equation for that reaction is [Pg.88]

On a quantitative basis, at the molecular level, the equation says [Pg.88]

The balanced equation shows two O, molecules and only one CH4 molecule, so it is reasonable that the number of O2 molecules that react Is twice the number of CH4 molecules that react. [Pg.88]

How many O, molecules react with 47 CH4 molecules according to the preceding equation Plan [Pg.88]

The balamed equation tells us that me CH4 molecule reacts with two O, molecules. We can construct two unit factors from this fact  [Pg.88]


I he calculation of chemical quantities based on chemical equations, termed stoichiometry, is the application of logic and arithmetic to chemical systems to answer questions such as the following ... [Pg.120]

The Third Edition includes more foundation work un formulae, the mole, calculations based on chemical equations and volumetric analysis for students starting A/AS Work from National Curriculum GCSE Science Double Award. [Pg.199]

Chemical Equations 3-2 Calculations Based on Chemical Equations... [Pg.81]

Why learn to write mole ratios They are the key to calculations that are based on chemical equations. Using a balanced chemical equation, mole ratios derived from the equation, and a given amount of one of the reactants or products, you can calculate the amount of any other participant in the reaction. [Pg.115]


See other pages where Based on Chemical Equations is mentioned: [Pg.456]    [Pg.173]    [Pg.174]    [Pg.175]    [Pg.176]    [Pg.177]    [Pg.178]    [Pg.180]    [Pg.182]    [Pg.184]    [Pg.186]    [Pg.4]    [Pg.28]    [Pg.92]    [Pg.93]    [Pg.95]    [Pg.113]    [Pg.92]    [Pg.93]    [Pg.95]    [Pg.113]    [Pg.8]    [Pg.38]    [Pg.185]    [Pg.109]    [Pg.107]    [Pg.88]    [Pg.89]    [Pg.107]   


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Chemicals equations

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