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Argon valence electrons

For example, nitrogen ( N ) has five valence electrons and needs three more electrons to complete its octet. Chlorine (-CL) has seven valence electrons and needs one more electron to complete its octet. Argon OArO already has a complete octet and has no tendency to share any more electrons. Hydrogen (H-) needs one more electron to reach its helium-like duplet. Because hydrogen completes its duplet by sharing one pair of electrons, we say that it has a valence of 1 in all its compounds. In general, the valence of an element is the number of bonds that its atoms can form. [Pg.189]

Chlorine would have to lose seven electrons to reach an electron configuration like that of neon. But if it gained one, it would have the same stable electron configuration as argon. So that is what chlorine does. If it meets an atom with a high-energy valence electron, such as sodium, the electron migrates to the chlorine atom and forms a chloride ion ... [Pg.83]

Sodium loses its valence electron and its electron configuration becomes identical to that of neon Is2 2s2 2p6. Likewise, the valence shell of chlorine becomes completely filled and its electron configuration resembles that of argon. As a result, during the reaction... [Pg.13]

Neon has eight valence electrons and all of them are paired, hence the valence orbitals of neon are completely filled. Therefore neon is very unreactive and does not bond with any other element. Similarly, the group 8A elements (noble gases) helium and argon are very unreactive. However, krypton and xenon may form bonds under certain conditions. [Pg.37]

The charges on the chlorine, potassium, and calcium ions result from a strong tendency of valence electrons to adopt the stable configuration of the inert gases, with completely filled electronic shells. Notice that the 3 ions have electronic configurations identical to that of inert argon. [Pg.40]

By contrast, the nonmetallic elements on the right side of the periodic table have many valence electrons and can most readily attain the stable configuration of the inert gases by gaining electrons. Table 5-3 compares three nonmetals to the inert gas argon. [Pg.49]

The pseudo-potentials used here are of the 1-dependent semi-local type, according to the expression of Barthelat and Durand The single valence electron pseudo-potential for the [Na ] core has been widely used in accurate standard valence calculations The argon atoms are represented via [Ar]... [Pg.373]

The sum in W runs over all polarizable cores (k=Na, Ar) a% is the dipole polarizability of core X, namely 0.9947 ao and 11.08 ao for sodium and argon respectively fx is the electrostatic field at center X, produced by the ion [Na ] and the single valence electron at relative distance r of core k. The electronic field is truncated by a stepwise cut-off function Fx, in order to avoid integral divergencies ... [Pg.373]

Outer electrons are called valence electrons and are represented by dots in Lewis symbols, as shown for carbon and argon in Figure 1.4. [Pg.26]

Atoms will gain, lose, or share valence electrons as to achieve an octet (in most cases) or electron configuration that is similar to that of a noble gas. For example, all of the following atoms and ions have 18 electrons and an electron configuration similar to that of a noble gas, argon S2, Cl1-, Ar, K1+, and Ca2+. All of these atoms/ions have an electron configuration of ls22s22p63s23p6. [Pg.73]

We have used 12 electrons to form the S—F bonds, which leaves 36 electrons. Since fluorine always follows the octet rule, we complete the six fluorine octets to give the structure on the right above. This structure uses all 48 valence electrons for SF6, but sulfur has 12 electrons around it that is, sulfur exceeds the octet rule. How can this happen There are several ways to approach this situation. The classical explanation for molecules like SFg involves using the empty 3d orbitals on the third-period elements. Recall that the second-row elements have only 2s and 2p valence orbitals, whereas the third-row elements have 3s, 3p, and 3d orbitals. The 3s and 3p orbitals fill with electrons in going from sodium to argon, but the 3d orbitals remain empty. For example, the valence-orbital diagram for a sulfur atom is... [Pg.618]

Most ionisation experiments have concentrated on the valence electrons of the target. However, experiments and calculations for the Is shell of neon and the n=2 shells of argon have been reported by Zhang et al. (1992). Fig. 10.8 shows an example. Here the 2p orbital of argon... [Pg.274]

By giving up its two valence electrons in the 4s orbital, calcium forms a stable cation with a 2+ charge that has an electron configuration like that of argon. [Pg.181]

Fluorine Because fluorine is the halogen with the lowest atomic number, it has a small atom that provides little shielding of its valence electrons from the nucleus. Fluorine is the most electronegative element on the periodic table that is, it has the greatest tendency to attract electrons. Thus, it is logical that fluorine also is the most active of all elements. In fact, it reacts with every element except helium, neon, and argon. [Pg.195]


See other pages where Argon valence electrons is mentioned: [Pg.4]    [Pg.16]    [Pg.19]    [Pg.136]    [Pg.136]    [Pg.75]    [Pg.68]    [Pg.56]    [Pg.110]    [Pg.17]    [Pg.397]    [Pg.398]    [Pg.399]    [Pg.209]    [Pg.866]    [Pg.866]    [Pg.102]    [Pg.79]    [Pg.11]    [Pg.199]    [Pg.114]    [Pg.411]    [Pg.446]    [Pg.213]    [Pg.333]    [Pg.1254]    [Pg.1255]    [Pg.3123]    [Pg.15]    [Pg.498]    [Pg.243]    [Pg.68]    [Pg.68]    [Pg.88]    [Pg.15]   
See also in sourсe #XX -- [ Pg.71 ]




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