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Why do Bonds Form

It is now time to analyze our first chemical bond. Why does a bond form A typical answer is that the energy decreases because the electrons primarily reside in between the [Pg.812]

Kinetic energy is lowest for a diffuse wavefunction. A. Lowest energy wavefunction, B. Intermediate energy, and C. Highest energy wavefunction. [Pg.813]

To understand the changes in kinetic energy and potential energy that occur when a bond forms, let s analyze the simplest of bonds, that in H2. The Hamiltonian for H2 is given in Eq. 14.12, where A and B represent the individual nuclei. Here we leave out the internuclear repulsion term, drawing on a simplification known as the Born-Oppenheimer approximation (discussed more in Section 14.2.1). [Pg.813]

The Schrodinger equation for H2 can be solved in an alternative coordinate system called confocal elliptical coordinates. Just as with the hydrogen atom, certain wavefunctions result, each of which has a distinct energy. [Pg.813]

Cross-sections along the x axis showing amplitude versus distance for A. Is orbital, and for the two lowest energy wavefunctions B. i/fg and C. i// for H2 relative to the center of the bond. The x axis is internuclear distance (Bohr radii). A represents H positions. Adapted from course notes by W. A. Goddard III, Nature of the Chemical Bond.  [Pg.813]


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