The electrostatic theorem and chemical binding

When the element of electronic charge — ep(r) dr is placed so that the first of the two following conditions is fulfilled, 

Two necessary conditions for a state to be bound are that the forces on the nuclei vanish at some R2 = R and that A ,2 0. Thus, in addition to the forces vanishing, there must be net attractive forces acting on the nuclei, that is, forces drawing the nuclei together and decreasing the separation R, over 

Qome range of internuclear separations for AEjj 0. The energy 

The Laplacian distributions for the shared interactions illustrated in Figs 7.15 to 7.17 clearly indicate the predominance of the concentration of electronic charge over the binding region for such interactions. In all of these molecules 0 over the binding region for each interacting pair of nuclei. 

Gauss s law of electrostatics states that the field exerted at a point external to a spherical charge distribution is equal to that which would be obtained if 

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