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Tetrahedron. See

In order to study in more detail the clay minerals, it is first helpful to review briefly the basic structural classification of the silicates in general. Although ultimately complicated, the general progression is logical, and is based on the degree of polymerization of the basic structural unit which is the Si04 tetrahedron (see below). The sequence runs as follows ... [Pg.104]

The structural unit for the simplest silicate, Si02, also known as silica, is the tetrahedron (see Figure 1.43). This is the result of applying Pauling s principles (Section... [Pg.60]

Fig. 2.25 Basic units of block structure [A] each block shares one edge of one octahedron at the corner of the block (see Fig. 2.19(c)) [B] each block shares three edges of two octahedra at the corner of the block (see Fig. 2.21) [C] each block shares one corner of one tetrahedron (see Fig. 2.23(c)). Fig. 2.25 Basic units of block structure [A] each block shares one edge of one octahedron at the corner of the block (see Fig. 2.19(c)) [B] each block shares three edges of two octahedra at the corner of the block (see Fig. 2.21) [C] each block shares one corner of one tetrahedron (see Fig. 2.23(c)).
Inspection of the tetrahedron (see Fig. 3.7) reveals the following symmetry elements and operations. [Pg.47]

These four occupied corners define a regular tetrahedron (see Problem 9.18) with the center of the tetrahedron being the point equidistant from the corners, which we showed as the location of the hole. This justifies the name tetrahedral hole. As the unit cell contains 8 tetrahedral holes, one in each minicube, and 4 gold atoms (Problem 10.1), there are 8 4- 4 = 2 tetrahedral holes per gold atom. [Pg.173]

It should be noted that the triply degenerate set of orbitals is labeled as t2 with no g subscript. The g subscript refers to gerade or even and to preservation of sign on reflection through a center of symmetry. Because there is no center of symmetry for a tetrahedron (see Chapter 2), the g subscript is dropped, giving the t2 and e designations. [Pg.467]

Because carbon uses Cwo kinds of orbitals (2 and 2p) to form bonds, wc expect methane to have two kinds of C-H bon< in fact, though, all Ihur C II bonds in methane are identical and are simtially oriented teward the comers of a regular tetrahedron (see Figure 1.6. How can we explain this ... [Pg.36]

There are four calcium and eight fluorine atoms in the unit cell. The number of molecules of CaF2 in the unit cell is four, so that, for all fluorite structure compounds, Z = 4. In this structure, each calcium atom is surrounded by eight fluorine atoms at the comers of a cube. Each fluorine atom is surrounded by four calcium atoms at the vertices of a tetrahedron (see also Chapter 7). A perspective view of the stmcture is shown in Figure 1.12a, and a projection of the stmcture down the c-axis in Figure 1.12b. [Pg.11]

These four extreme types of bonding can be represented on the four apexes of a tetrahedron. (See Eigure 2.)... [Pg.161]

Roussin s black salt has a more complex cluster structure. The [Fe4(NO)7S3] displays an incomplete cubane geometry of the anion cluster and consists of a tetrahedron of iron atoms with sulfide ions on three faces of the tetrahedron (see Scheme 3). The point group symmetry of the anion is Csv Three iron atoms... [Pg.55]

Each carbon-hydrogen bond in methane arises from an overlap of a C (sp ) and an H (li) orbital. The sharing of two electrons in this overlap region creates a sigma (a) bond. The four equivalent sp orbitals point toward the comers of a regular tetrahedron (see I Figure 1.5). [Pg.34]

It is important at once to get a true picture of what these molecules look like in three dimensions. We must realize that in these compounds the carbon valencies have fixed directions and the bonds are equidistant in space, pointing from the centre to the corners of a tetrahedron (see Fig. 4). [Pg.29]

White phosphorus, the longest known form, is the most volatile and reactive form of the solid, and is closely related to the liquid and vapour phases of the element into which it readily transforms. It is soluble in organic solvents but practically insoluble in water. White P is tetra-atomic and the P4 molecule forms a tetrahedron (see below). [Pg.93]

The trans form of C1P=PC1 (4.286b) has been stabilised in the form of a metal complex (8.361c). There is NMR evidence for the existence of species such as (4.286c) which may be based on the P4 tetrahedron (see isostructural P5I+) [53]. Other characterised halides include (4.286d,e). [Pg.160]

In Section 1.2.4, it was shown how the four sp hybridized orbitals of carbon could form a regular tetrahedron (see Figure 1.4) with a bond length of 0.154nm. Each tetrahedron can then combine with four other tetrahedra to form the strongly bonded covalent structure of diamond (Figure 2.7), which can have either cubic or hexagonal symmetry. [Pg.20]

Methane (4, CH4) is the prototypical model used to understand a covalent carbon. As noted several times, the four hydrogen atoms are distributed around carbon in the shape of a regular tetrahedron (see Figure 3.10). The bond angles have been measured to be 109°20 for all H-C-H bond angles. All four C-H bond lengths are the same (1.094 A 109.4 Remember that these facts... [Pg.65]

In the tetrahedral point group d, cL, d,y) and (p py, Pz) both transform according to the tz irreducible representation and generate three d-p hybrids which point towards the vertices of a cube not utilized by the tetrahedron (see Fig. 11). [Pg.33]


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