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Tetrahedral electronic energy levels

Figure 27 (a) The splitting of the one-electron energy levels of the copper(II) ion in crystal fields of axial and rhombic symmetry (b) The splitting of the one-electron energy levels of the copper(II) ion in crystal fields of tetrahedral, cu-distorted octahedral, trigonal octahedral and trigonal bipyramidal symmetry... [Pg.655]

Tetrahedral Co (II) complexes absorb at lower frequencies than octahedral complexes with weak or moderately strong ligands of similar positions in the spectrochemical series. This is due to the smaller splitting of the -electron energy levels in the former case. An increase of ligand field strength with retention of symmetry and spin state leads to a shift of the spectrum to higher frequencies on both cases. [Pg.158]

Copper(II) has a 3d9 electronic configuration. In principle, pure octahedral and tetrahedral symmetries can never be observed because Jahn-Teller distortions (see Section 3.3.1) remove the orbital degeneracy of the ground state. The separation of the electronic energy levels depends on the coordination number and stereochemistry, as well as on the nature of the ligands. However, the ground state orbital is always well isolated from the excited states, and therefore the electronic relaxation mechanisms are relatively inefficient. Copperfll) complexes have thus relatively sharp EPR signals, and it is often possible to record these spectra at room temperature. [Pg.174]

Fig. 4.10. a) Electron energy levels for a Pt atom on a tetrahedral comer b) FMO representation of the oxidation of CO over this atom. [Pg.60]

One-electron energy levels associated with metal d orbitals in complexes of various symmetries (a) octahedral (b) tetrahedral (c) tetragonal distortion of an octahedron (d) trigonal distortion of an octahedron (e) trigonal distortion of a tetrahedron. [Pg.293]

FIGURE 16.28 Tbe energy levels of the d-orbitals in a tetrahedral complex with the ligand field splitting A,. Each box (that is, orbital) can hold two electrons. The subscript g is not used to label the orbitals in a tetrahedral complex. [Pg.802]

In a nickel-containing enzyme various groups of atoms in the enzyme form a complex with the metal, which was found to be in the +2 oxidation state and to have no unpaired electrons. What is the most probable geometry of the Ni2+ complex (a) octahedral (b) tetrahedral (c) square planar (see Exercise 16.96) Justify your answer by drawing the orbital energy-level diagram of the ion. [Pg.817]

The Li + dication with two electrons AN + 2, N= 0) adopts a tetrahedral structure [42]. The single molecular orbital composed of four i-orbitals at the lowest energy level in the tetrahedron is lower than that in the square. The number of the in-phase relations between the. y-orbitals is greater in the tetrahedron. [Pg.299]

Figure 1.4 Approximate energy levels for d electrons in octahedral, tetrahedral, and square-planar fields. Figure 1.4 Approximate energy levels for d electrons in octahedral, tetrahedral, and square-planar fields.
A low-spin to high-spin transition relates to the crystal field splitting of the d-orbitals in an octahedral or tetrahedral crystal field. However, even in cases where the energy difference between two spin states is much larger, electronic transitions are observed. An atom with total spin quantum number S has (22 + 1) orientations. In a magnetic field the atom will have a number of discrete energy levels with... [Pg.258]

F ure 5.6 The energy-level scheme for the crystal field splitting of a d electron in different symmetries (a) octahedral, (b) tetrahedral, and (c) cubic. [Pg.159]

Splitting of the energy levels. Both an octahedral complex (two electrons in orbitals) and a tetrahedral complex (four electrons in orbitals) are less favorable in this case. [Pg.77]

Although promotion and hybridization are connected in the formation of methane from carbon and hydrogen, care should be taken to distinguish between them. Promotion involves the addition of energy to raise an electron to a higher energy level in order that the two additional bonds may form. It is conceivable that after promotion the carbon atom could lave formed three bonds with the three p orbitals and the fourth with the s orbital. That carbon forms tetrahedral bonds instead is a consc-... [Pg.87]


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See also in sourсe #XX -- [ Pg.51 ]

See also in sourсe #XX -- [ Pg.5 , Pg.51 ]




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