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Temperature Derivatives of Pressure and Volume

It follows that in the limit of absolute zero, the entropy of a perfect crystalline substance must be independent of changes in pressure or volume (or any other variable of state except T). Thus, [Pg.265]

In other words, the temperature gradients of the pressure and volume vanish as absolute zero is approached. [Pg.265]

In the statement that we have adopted for the third law, it is assumed (arbitrarily) that the entropy of each element in some crystalline state is zero at 0 K. Then for every perfect crystalline substance, the entropy is also zero at 0 K. Consequently we can set S(0 K) in Equation (11.14) equal to zero. Thus, we may write [Pg.265]

To calculate the entropy of a substance at a temperamre at which it is no longer a sohd, it is necessary to add the entropy of transformation to a hquid or gas and the subsequent entropies of warming. The same procedure would apply to a solid that exists in different crystalline forms as the temperature is increased. The procedure can be illustrated by some sample calculations. [Pg.266]


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