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Systems, Orbital Symmetry, and Ultraviolet Spectroscopy

15-1 Look for 1) the number of double bonds to be hydrogenated—the fewer C=C, the smaller the A// 2) conjugation—the more conjugated, the more stable, the lower the AH 3) degree of substitution of the alkenes—the more substituted, the more stable, the lower the AH. [Pg.317]

15-2 Reminder H—B is used to symbolize the general form for an acid, that is, a protonated base B is the conjugate base. [Pg.317]

The central carbon atom makes two 7C bonds with two p orbitals. These p orbitals must necessarily be perpendicular to each other, thereby forcing the groups on the ends of the allene system perpendicular. [Pg.318]

15-4 Carbocation stability depends on conjugation (benzylic, allylic), then on degree of carbon carrying the positive charge. [Pg.318]

The most basic species in the reaction mixture will remove this proton. The oxygen of ethanol is more basic than bromide ion. [Pg.319]

The key step is hydride shift from a 2° carbocation to a 2° allylic, resonance-stabilized carbocation, which can subsequently lose a proton to form a conjugated diene. [Pg.317]


CONJUGATED SYSTEMS, ORBITAL SYMMETRY, AND ULTRAVIOLET SPECTROSCOPY 667... [Pg.13]

CHAPTER 15 Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy... [Pg.668]




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