Stoichiometry problems percent yield

The problem asks for a yield, so we identify this as a yield problem. In addition, we recognize this as a limiting reactant situation because we are given the masses of both starting materials. First, identify the limiting reactant by working with moles and stoichiometric coefficients then carry out standard stoichiometry calculations to determine the theoretical amount that could form. A table of amounts helps organize these calculations. Calculate the percent yield from the theoretical amount and the actual amount formed. 

Example 10.4 shows how percent yield calculations can be combined with equation stoichiometry problems. 

CIA Demonstration Self-Inflating Hydrogen Balloons Theoretical Yield and Percent Yield A Problem Involving the Combined Concepts of Stoichiometry... 

We can choose to make this a two-part problem. We are given the actual yield. The stoichiometry problem for finding MgO must be based on theoretical yield. What is our link between actual and theoretical yield Percent yield gives us the conversion factor 81.3 g (act)/100 g (theo). First we will find the theoretical yield from the actual yield then we will calculate the amount of reactant by stoichiometry. 

---

See also in sourсe #XX -- [ , , , , , ]

---