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Standardization Using a Standard Solution

In the case of standardization using a standard solution, it is a volume of the substance titrated that is measured into the reaction flask. Since volume in liters multiplied by molarity gives moles (see Equation (4.19)), [Pg.73]

since volume in liters multiplied by normality gives us equivalents (see Equation (4.23)), Equation (4.25) becomes [Pg.74]

As in the discussion accompanying Equation (4.2), the volume of titrant and the volume of substance titrated may be expressed in any volume unit as long as they are both the same unit. Thus we have [Pg.74]

The experiment is performed by precisely measuring the volume of the solution of substance titrated (either the solution to be standardized or the known standard solution) into the reaction flask and then titrating it with the other solution. At the end point, VT and Vst are known and one of the two concentrations is known (the known standard). Thus the other concentration can then be calculated. See Workplace Scene 4.1. [Pg.74]

Standardization of a solution of sulfuric acid required 29.03 mL of 0.06477 M NaOH when exactly 25.00 mL of H2S04 was used. What is the molarity of H2S04 Refer to Equation (4.5) for the reaction involved. [Pg.74]


See other pages where Standardization Using a Standard Solution is mentioned: [Pg.73]    [Pg.499]   


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