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Staged operations with linear equilibria

SO that the bracketed terms in Equation 7.10e and Equation 7.10f are identical and, consequently, S- = S2. Hence, it is seen that in this case of a two-stage cascade with linear equilibrium, optimum operation calls for the use of equal amounts of adsorbent given by either Equation 7.10e or Equation 7.10f. [Pg.317]

E. Check. This problem can also be solved anal5 cally. We want to solve the linear equilibrium equation y = mx simultaneously with the linear operating equation for each stage, y = -(R/Ej)x +... [Pg.528]

A single-stage liquid-extraction operation with a linear equilibrium-distribution curve (F = mX... [Pg.136]

These equations are linear, with slopes L/V and L /V. They are referred to as operating lines, and give the relationship between the liquid and vapour compositions between stages. For an equilibrium stage, the compositions of the liquid and vapour streams leaving ... [Pg.505]


See other pages where Staged operations with linear equilibria is mentioned: [Pg.261]    [Pg.177]    [Pg.137]    [Pg.168]    [Pg.67]    [Pg.198]    [Pg.614]    [Pg.198]    [Pg.93]    [Pg.766]    [Pg.198]    [Pg.285]    [Pg.184]    [Pg.17]    [Pg.1451]    [Pg.1731]    [Pg.1732]    [Pg.1741]    [Pg.310]    [Pg.830]    [Pg.252]    [Pg.45]    [Pg.46]    [Pg.55]    [Pg.512]    [Pg.1448]    [Pg.1725]    [Pg.1726]    [Pg.1735]    [Pg.324]   
See also in sourсe #XX -- [ Pg.323 ]




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