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Solution to Design Problem IX

We first determine the arrangement of the sheets in the mold and the number of sheets required. The total length of the mold including the curved sections is 1.628 m. The breadth of the mold as given is 64.8 cm, and the final thickness is given as 3.2 mm. Hence, the total volume of the final part will be 3.3758 x 10 m. Because the mold is 64.8 cm in breadth, we can place three sheets across this dimension. If we fill the flat section of the mold with 5.23 sheets that are 19.1 cm in width, they will not fill the curved section of the [Pg.332]

FIGURE 10.22 Dynamic oscillatory shear properties (i.e., I I and G ) of Azdel PM 10300 obtained at three temperatures. [Pg.333]

We next formulate the solution to the heat transfer problem. Although the blanks will be stacked two deep in the compression mold, they will pass through the oven as single blanks. The problem to be solved is that of one-dimensional transient heat conduction in which the top and bottom surfaces are subjected to radiation heating. Following the development in Sections 5.3 and 5.4, the differential equation for the heat transfer process becomes [Pg.333]

FIGURE 10.21 Dynamic mechanical thermal analysis of polypropylene reinforced with 30 wt% glass fiber mat (Azdel PM 10300). Measurements were made at an angular frequency of 1.0 rad/s on rectangular strips in a rheometer operated in the torsional mode. [Pg.333]

To solve Eq. 10.89 we use the numerical approach discussed in Section 5.4. We can adopt the numerical solutions used to solve Example 5.5 (see the solutions for problems in Chapter 5). The main differences are in the form of the heat transfer coefficient, hi, which is given in Eq. 10.92, the expression for the surface node temperature changes to [Pg.334]


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