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Solution of the Steady State Equations

The steady-state equations can be manipulated to take the form of heat generation and heat removal functions, i.e., a modified Van Heerden diagram. This manipulation can be carried out in different ways, all leading to the same results and here we choose to obtain the heat generation and removal functions of the regenerator as a function of the reactor [Pg.445]

Compute x D from the following equation which can easily be derived from equation (7.29). [Pg.445]

Calculate x2d from equation (7.30) in the following equivalent explicit form  [Pg.445]

Calculate the rate of coke formation Rcf from equation (7.43) and Ta from equation (7.31). [Pg.445]

Calculate AHcr from equation (7.45) and Yqd from equation (7.32). [Pg.446]


That is, we are interested in y(r) = Y(r, oo) and the corresponding reaction rate, Kq — K(oo). The former satisfies the equation (3.2.39) with the boundary conditions (3.2.40). As it is clear from Chapter 3, the solution of equation (3.2.39) defines uniquely the survival probability u>(l oo) of geminate pairs. In a particular case of the Coulomb interaction, the solution of the steady-state equation (3.2.39) is simplified since for the unscreened Coulomb potential the relation V2C/(r) = 0 holds. Integrating the differential equation... [Pg.187]

Normally the easiest algebra is chosen here [CH ] was found first from solution of the steady state equations, and so either (a) or (b) is chosen in preference. [Pg.220]

The regions for the multiplicity of steady states represented in Figs. 2 and 3 were constructed from the numerous solutions of the steady state equation (7) by varying Pa>, Pco, and T within a given range [140]. Later [141], a more efficient computational method for the construction of the boundary for the multiplicity region in the plane of the parameters PQi and PCo was used. This method makes essential use of the specificity in the dependence of eqn. (7) on Po, and Pco- Equation (7) can be represented as... [Pg.328]

Solution of the steady-state equations for [X ] (i.e. with d[X ]/df = 0) provides an expression for the luminescence emission intensity, Iium, in terms of the intensity of absorbed radiation, iabs, where A is the Einstein coefficient for spontaneous emission ... [Pg.30]

The basic idea is to describe a snapshot of the flow in a stirred vessel with a fixed relative position of blades and baffles. It is assumed that the main flow characteristics of a stirred vessel at the particular time instant in question can be captured approximately from the solution of the steady-state equations, provided that artificial cell volnme adjustments and momentum sources are implemented to represent the effect of the impeller rotation. [Pg.731]

Solution of the steady state equations gives the rate of formation of reaction products Rp as... [Pg.77]

Suppose now that one is looking for bifurcations with codimension t. One variable only will be necessary to span the phase space. In other words,we shall first consider the interaction of steady states in phase space only in one dimension. In that case the solutions of the steady state equations will move along a line passing through the reference state Xi = 0, which can be projected out on any coordinate... [Pg.66]

The working lines are the solutions of the steady state equations for the reactor. For the mass balance we may write ... [Pg.118]

Note, however, that it is possible to have a solution of the steady state equation, but not have a long-run distribution. [Pg.108]

Equation 5.16 says that the Uj area solution of the steady state equation. Thus the theorem says that if a unique non-zero solution of the steady state equation exists the chain is ergodic, and vice-versa. A consequence of this theorem is that time averages from an ergodic Markov chain will approach the steady state probabilities of the chain. Note, however, for an aperiodic irreducible Markov chain that has all null recurrent states, the mean recurrence times are infinite, and hence Uj = 0 for such a chain. The only solution to the steady state equation for such a chain is Uj = 0 for all j. It is very important that we make sure all chains that we use are ergodic and contain only positive recurrent states Note also that the theorem does not say anything about the rate the time averages converges to the steady state probabilities. [Pg.114]

We want to find a Markov chain that has the posterior distribution of the parameters given the data as its long-run distribution. Thus the parameter space will be the state space of the Markov chain. We investigate how to find a Markov chain that satisfies this requirement. We know that the long-run distribution of a ergodic Markov chain is a solution of the steady state equation. That means that the long-run distribution 7T of a finite ergodic Markov chain with one-step transition matrix P satisfies the equation... [Pg.128]

Numerical solutions of the steady-state equations (4) or (4 ) can be obtained using the method proposed by Sundaram et al. [60] which reduces these equations to two first order ones. Writing a= V jD and and also z=dSj X and... [Pg.443]


See other pages where Solution of the Steady State Equations is mentioned: [Pg.129]    [Pg.175]    [Pg.177]    [Pg.20]    [Pg.276]    [Pg.157]    [Pg.445]    [Pg.276]    [Pg.420]    [Pg.161]    [Pg.108]    [Pg.121]   


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Solution of equations

Solution state

States of solution

Steady solution

The State Equations

The Steady State

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