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Second cycle work input

Thus we see the pattern reported in Fig. 4.S2 is confirmed and greatly extended in its reach. For most of the materials in the present study there is a common linear relationship between second cycle hysteresis and second cycle work input, and this... [Pg.147]

The second term on the right-hand side of the lost-work equation. Eg, (9.38T for the propane refrigeration cycle is the reversible work input that corresponds to the heat input. It is... [Pg.1096]

Fig. 432 Hysteresis versus work input for the second load/unload cycle to e = 3. Symbols as in Fig. 4.24. Fig. 432 Hysteresis versus work input for the second load/unload cycle to e = 3. Symbols as in Fig. 4.24.
Fig. 4.37 Hysteresis versus work input for second cycle load/unload to increasing emax, in the pseudo-cycUc experiments of Phase 2. Symbols are as in Fig. 4.24. The two dashed lines are linear regressions through data for sub-sets of the materials A (all materials except PU7 and PUS), and B (PU7 and PUS)... Fig. 4.37 Hysteresis versus work input for second cycle load/unload to increasing emax, in the pseudo-cycUc experiments of Phase 2. Symbols are as in Fig. 4.24. The two dashed lines are linear regressions through data for sub-sets of the materials A (all materials except PU7 and PUS), and B (PU7 and PUS)...
In principle, a de novo protein structure determination requires one round of 7 Candid cycles. This is realistic for projects where an essentially complete chemical shift list is available and much effort was made to prepare a complete high-quality input of NOESY peak lists. In practice, it turned out to be more efficient to start a first round of Candid analysis without excessive work for the preparation of the input peak list, using an slightly incomplete list of safely identifiable NOESY cross peaks, and then to use the result of the first round of Candid assignment and structure determination as additional information from which to prepare an improved, more complete NOESY peak list as input for a second round of 7 Candid cycles. [Pg.63]

Let the angular frequency (in rad corresponding to 50 Hz be o>. The power input P is given by the work done per cycle (integral of force x displacement) multiplied by the number of cycles per second. If F is the oscillating force and x the relative displacement of the ends of the bar which results. [Pg.131]


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See also in sourсe #XX -- [ Pg.2 , Pg.136 ]




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