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Scenario 6—There are Three Electrons in a Triply Degenerate Orbital

6 Scenario 6—There are Three Electrons in a Triply Degenerate Orbital [Pg.547]

The symmetries of the resulting terms will once again be identical to the overall direct product of the occupied orbitals. The spin multiplicity will either be 4 (if all three electrons have parallel spins) or 2. The characters for the doublet state under each operation in the sub-rotational point group are given by Equation (16.13), while those for the quartet state are given by Equation (16.14). [Pg.547]

TABLE 16.21 Term symbols for the f2g g° electron configuration in the strong-fieid iimit for an octahedrai LF. [Pg.547]

Solution. The three strong-field electron configurations are t2g eg°, t2g eg, and t2g°6g. The configuration will have a degeneracy of 6 /(2 4 ) = 15, [Pg.548]

Correlation diagram for the fi electron configuration in an octahedral LF. [Reproduced from Figgis, B. N. Flitchman, M. A. Ligand Field Theory and Its Applications, Wiley-VCFI New York, 2000. This material is reproduced with permission of John Wiley Sons, Inc.] [Pg.548]




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A Orbital

A* orbitals

Degenerate orbits

Electron orbitals

Electron, orbiting

Orbital a orbitals

Orbital degenerate

Orbital electrons

Orbitals degenerate

Scenario, scenarios

Scenarios

Three-electron

Triply degenerate orbitals

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