Running a concession stand

Picture this It s game night, and you ve made a dash to the food vendor to get a quick snack. So did half the people in the stadium. Now you have time to stand in line and wait and ponder the problem of combining different foods and drinks available in the concession stand so that you can spend every penny of the money in your pocket — no more, no less. 

The Problem Stan had exactly 20.40 in his pocket and managed to spend it all at the concession stand. He bought three hot dogs, two servings of cheese fries, and one large drink for that amount of money. One hot dog costs 1.80 more than one serving of cheese fries. And a drink costs 1.20 less than a hot dog. How much did each item cost  

The number of items have to be multiplied by their respective prices, and the costs totaled. Set that total equal to 20.40 to solve for the individual prices. Let the cost of cheese fries be represented by c. Then a hot dog costs c + 1.80. A drink is 1.20 less than a hot dog, so it costs c + 1.80 - 1.20 = c + 0.60. 

So cheese fries cost 2.40, the hot dogs are 1.80 more than that (or 4.20), and the drink is 0.60 more than the fries (or 3). 

The Problem You re buying supplies for the concession stand Friday night and need to purchase candy and pretzels and gum in bulk. Twix candy bars are 354 each if you buy a case of 36. M M s bags are 364 each if you buy a case of 48. Pretzels are 194 a bag if you buy a case of 30. Cookies are 244 a package if you buy a case of 33. And gum costs 184 a pack if you buy a case of 40. You buy the same number of cases of cookies and gum. You buy twice as many cases of M M s as cookies. You buy two less than twice as many cases of pretzels as cookies. And you buy five fewer cases of Twix than M M s. If you spend 270.72 on all these supplies, then how many individual items do you have on hand to sell Friday night  

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