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Recap on calculating the equilibrium constants using statistical thermodynamics

Recap on calculating the equilibrium constants using statistical thermodynamics [Pg.182]

The reactions which we have encountered, with the exception of the inter-phase reactions, take place in the solid phase, so all the components in the reaction are components of the same solid solution. [Pg.182]

For such a solution, the variation in volume due to the reaction is negligible, and therefore we will have  [Pg.182]

We can express the Helmholtz energy using statistical thermodynamics, remembering that the molecules of solid are considered to be discernible molecules. If we have a population of Nj molecules of the species / which each have a molecular partition function z , then the Helmholtz energy of that species / is written as  [Pg.182]

In this expression, the solution is taken to be perfect, because no account is taken of an enthalpy of mixing. [Pg.182]




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