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Pores triangular

Fig. 6.10 Pore density versus silicon electrode doping density for PS layers of different size regimes. The broken line shows the pore density of a triangular pore pattern with a pore pitch equal to twice the SCR width for 3 V applied bias. Note that only macropores on n-type substrates may show a pore spac-... Fig. 6.10 Pore density versus silicon electrode doping density for PS layers of different size regimes. The broken line shows the pore density of a triangular pore pattern with a pore pitch equal to twice the SCR width for 3 V applied bias. Note that only macropores on n-type substrates may show a pore spac-...
Fig. 10.17 Microstructured bar of macropor-ous silicon with a waveguide oriented in the T-K direction. The triangular lattice of pores... Fig. 10.17 Microstructured bar of macropor-ous silicon with a waveguide oriented in the T-K direction. The triangular lattice of pores...
Further, it is known that real-world capillaries or pores are not always circular shaped. In fact, in oil reservoirs, the pores are more triangular shaped or square shaped than circular. In this case, the rise in capillaries of other shapes, such as rectangular or triangular (Birdi et al 1988 Birdi, 1997, 2002) can be measured. These studies have much significance in oil recovery or water treatment systems. In any system in which the fluid flows through porous material, it would be expected that capillary forces would be one of the most dominant factors. [Pg.20]

Because the shape of the pores is not exactly cylindrical, as assumed in the derivation of Equation 3.12, the calculated pore size and pore size distribution can deviate appreciably from the actual values shown by electron microscopy. If a pore has a triangular, rectangular or more complicated cross-section, as found in porous materials composed of small particles, not all the cross-sectional area is filled with mercury due to surface tension mercury does not fill the comers or narrow parts of the cross-section. A cross-section of the solid, composed of a collection of nonporous uniform spheres during filling the void space with mercury is shown in Figure 3.3. Mayer and Stowe [15] have developed the mathematical relationships that describe the penetration of mercury (or other fluids) into the void spaces of such spheres. [Pg.41]

Other high temperature simulations of methane in this model of graphitized carbon black include studies of sorption in pores with triangular cross sections. [Pg.595]

M. J. Bojan and W. A. Steele, Computer Simulation Studies of the Sorption of Kr in a Pore of Triangular Cross Section, in Proceedings of the Fourth International Conference on Fundamentals of Adsorption, ed. M. Suzuki (Kodansha Publishers, Tokyo, 1993), 51-58. [Pg.621]

In what follows we describe the simulation model for N2 adsorption in activated carbons for slit-like and triangular section pores and the characterization method to find the MSD from adsorption data by fitting simulated isotherms to experimental ones... [Pg.392]

For the triangular geometry, we consider the adsorption space as being a prism, whose cross section is an equilateral triangle, formed by three semi-infinite walls, each wall consisting of 4 graphite planes. The size of the pore, d, is taken as the diameter of the inscribed circle The axis of the pore runs along the xe (0,/-) coordinate, with L =21 nm and periodic boundary conditions in x. [Pg.393]

Calculation of meniscus curvature in pores bordered by spheres is still too difficult for a full mathematical analysis. However, there is one class of pore geometry that is complex but can still be analysed by a simple theory. It is the geometry of a uniform non-axi-symmetric tube (or tubes). For example the capillary behaviour of a tube of triangular cross-section can be analysed quite simply. Even tubes assembled from parallel rods do not cause much difficulty. [Pg.497]

Schulz and Asumnaa (48), based on their SEM observation, assumed that the selective layer of an asymmetric cellulose acetate membrane for reverse osmosis consists of closely packed spherical nodules with a diameter of 18.8 nm. Water flows through the void spaces between the nodules. Calculate the water flux by Eq. (30) assuming circular pores, the cross-sectional area of which is equal to the area of the triangular void surrounded by three circles with a diameter of 18.8 nm (as shown in Eig. 8). [Pg.227]

Calculate the radius of the circular pore whose cross-sectional area is equal to the triangular area calculated above. [Pg.227]


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See also in sourсe #XX -- [ Pg.9 , Pg.10 , Pg.11 , Pg.12 , Pg.13 , Pg.14 ]




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Triangularity

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