Pascal unit

The answer is B. The objective of this question is to convert the given pressure value (in mmHg) to Pascal units. In order to do this, we should first convert the given value into atmospheres. Since one atm equals 760 mmHg, 1330 mmHg equals 1.75 atm. The conversion of atmospheres to Pascal units is given in the question. The conversion is ... 

Convert the following pressure readings from inches of mercury units to psi and Pascal units ... 

Pascal Unit of pressure equal to 1 newton per square meter. 

The forces and subsequent work terms have some simple examples. Consider a postage stamp, which weighs about 1 g and is about 1 cm x 1 cm in size. It requires about 1 dyne of force to lift it from the horizontal position to the vertical position, as in turning it over. One dyne of force through 1 cm gives 1 erg, the amount of work done. Modulus is usually reported in dynes/cm, in terms of force per unit area. Frequently the Pascal unit of modulus is used, 10 dynes/cm = 1 Pascal. 

By using pressures in units of atm and volumes in units of L, we get a unit of work in L-atm. This is not a common work unit. The SI unit for work is the joule, J. However, using the various values of R from the previous chapter, it can be shown that 1 L-atm = 101.32 J. This conversion factor is very useful to get work into its proper SI units. If volume were expressed in units of m and pressure in pascals, units of joules would be obtained directly because... 

Theoretically, the dimensionality for elasticity, stress and hardness is identical in Pascal unit (energy density) but at different states. The ideal form represents the intrinsic property change without experimental artifacts being involved. However, the softening and the slope transition in the IHPR plastic deformation arises from the extrinsic competition between activation of and resistance to glide dislocations, which is absent in the elastic deformation in particular using the non-contact measurement such as SWA techniques and Raman measurements. 

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