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Newton wheel

A 1,000 kg (metric ton) car accelerating from 0—30 m/s (68 mph) in 6 seconds, thus requires an average force of 5,000 neivtoiis. This is a force approximatel y half the tveight of the car. It is likel y that the car would burn rubber as the drive wheels spun on the road during this acceleration. To accelerate to the same speed in 12 seconds would require a force of onl y 2,500 newtons. [Pg.965]

Much of Newton s work involved rotational motion, particularly circular motion. The velocity s direction constantly changes, requiring a centripetal acceleration. This centripetal acceleration requires a net force, the centripetal force, acting toward the center of motion. Centripetal acceleration is given by a(central)=v /R where v is the velocity s magnitude and R is the radius of the motion. Hence, the centripetal force F(central) = mv /R, where m is the mass. These relationships hold for any case of circular motion and furnish the basis for thrills experienced on many amusement park rides such as ferris wheels, loop-the-loops, merry-go-rounds, and any other means for changing your direction rather suddenly. Some particular examples follow. [Pg.546]

The rotation of the wheel is governed by Newton s law F = ma, expressed as a balance between the applied torques and the rate of change of angular momentum. Let / denote the moment of inertia of the wheel. Note that in general / depends on... [Pg.306]

It was widely appreciated by Newton and his contemporaries that the compressive effect of the Cartesian aether was equivalent to some hypothetical force, often likened to gravity, that puUs a planet towards the central star and bends its rectilinear motion around into a closed curve. The magnitude of such a force had to be sufficient to balance the centrifugal, potter s wheel, effect and so prevent the rotating planet firom escaping. It became vitally important to calculate the centripetal acceleration that was needed to stabilize such a closed orbit. [Pg.36]

Melt strength was measured at 190 °C on a Gottfert Rheotens . The barrel length of the rheometer was 285 mm and width ca. 12 mm. A 30/2 die for the extrusion of the blend was utilized. The sample was allowed to melt in the barrel for ten minutes, followed by extrusion through the die at a rate of 0.27 mm/s (shear rate of ca. 38 s" ). As the sample extruded out of the die, it passed through the wheels of the Rheotens , which pulled the molten polymer strand in a downward motion. As the wheel velocity increased, the force required to pull the molten extrudate was measured in centi-Newtons or cN. [Pg.2239]


See other pages where Newton wheel is mentioned: [Pg.11]    [Pg.12]    [Pg.11]    [Pg.12]    [Pg.1084]    [Pg.195]    [Pg.327]    [Pg.1184]    [Pg.1]    [Pg.68]    [Pg.806]    [Pg.272]    [Pg.109]    [Pg.229]    [Pg.65]   
See also in sourсe #XX -- [ Pg.11 ]




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