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Lumped Problems Bi

An illustrative example for these problems is the cooling of a small metal ball (or billet) in a constant-temperature (large) bath. Let the ball, heated to a uniform temperature To, be quenched into the bath at temperature 2, . [Pg.126]

Consider the entire ball to be a lumped system. The first law of thermodynamics, Eq. (1-10), applied to this system yields (Fig. 3.2), [Pg.126]

in terms of the definitions of specific heat at constant volume and at constant pressure, [Pg.127]

That is why we usually refer to the specific heat for solids and liquids without any reference to volume or pressure [a fact already used in the development leading to Eqs. (2.148) and (2.149)]. Thus, [Pg.128]

Finally, Newton s law, inserted into Eq. (3.3), gives the governing equation, [Pg.128]


When Bi zero dimensional or lumped model [2, 11], On the other hand, if Bi 1, the fluid can be considered isothermal and Ts = Too, which changes the convection boundary condition to a thermal equilibrium condition. [Pg.221]


See other pages where Lumped Problems Bi is mentioned: [Pg.126]    [Pg.127]    [Pg.129]    [Pg.131]    [Pg.133]    [Pg.137]    [Pg.139]    [Pg.126]    [Pg.127]    [Pg.129]    [Pg.131]    [Pg.133]    [Pg.137]    [Pg.139]   


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