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Lorentz symmetric regauging

B. Breaking the Lorentz Symmetric Regauging Condition Reexamining the Common Dipole... [Pg.639]

In short, we must violate the Lorentz symmetric regauging condition during the excitation discharge represented by operation 2 of an open system far from thermodynamic equilibrium. [Pg.646]

That our normal EM power systems do not exhibit COP> 1.0 is purely a matter of the arbitrary design of the systems. They are all designed with closed current loop circuits, which can readily be shown to apply the Lorentz symmetric regauging condition during their excitation discharge in the load. Hence all such systems — so long as the current in the loop is unitary (its charge carriers have the same m/q ratio) — can exhibit only COP< 1.0 for a system with internal losses, or COP =1.0 for a superconductive system with no internal losses. [Pg.724]

Such was H. A. Lorentz s prestige that, once he advanced symmetrical regauging of the Maxwell-Heaviside equations, it was rather universally adopted by electrodynamicists, who still use it today see, for example, Jackson [15]. [Pg.703]


See other pages where Lorentz symmetric regauging is mentioned: [Pg.639]    [Pg.642]    [Pg.643]    [Pg.646]    [Pg.646]    [Pg.680]    [Pg.692]    [Pg.702]    [Pg.716]    [Pg.639]    [Pg.642]    [Pg.643]    [Pg.646]    [Pg.646]    [Pg.680]    [Pg.692]    [Pg.702]    [Pg.716]    [Pg.642]    [Pg.668]    [Pg.677]    [Pg.703]    [Pg.723]    [Pg.715]   


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