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Logic analyzer

Let s try logic. Analyze the ozonolysis products carefully—what do you see There are only two methyl groups, so one of the three terminal carbons in the skeleton (C-8, C-9, or C-10) has to be a =CH2. Do we know which terminal carbon has the double bond Yes, we can deduce that. If C-10 were double-bonded to C-4, then after ozonolysis, C-8 and C-9 must still be attached to C-7. However, in the ozonolysis products, there is no branched chain, that is, no combination of C-8 + C-9 + C-7 + C-1. What if C-7 had a double bond to C-1 Then we would have acetone, CH3COCH3, as an ozonolysis product—we don t. Thus, we can t have a double bond from C-4 to C-10. One of the other terminal carbons (C-8) must have a double bond to C-7. [Pg.185]

Memory examine and modify Emulator Processor register examine and modify Single Step Execution Software Breakpoints Trace Analysis Logic Analyzer Functions Disassembly Functions... [Pg.70]

MESFETs with a transconductance of 3.9 iS/mm. Two MESFETs were connected, including one FET as a current source, to observe a gain (Voui/Vm) of approximately 2. Using a logic analyzer, two FETs were connected with load resistance to observe NAND operation in 1994 by Glass et al. (74). [Pg.402]

Break-out box IC-tester Logic analyzer Prom programmer... [Pg.44]

So what to do if your GPIB system doesn t work, and you don t have a logic analyzer Let s go step by step ... [Pg.228]


See other pages where Logic analyzer is mentioned: [Pg.113]    [Pg.55]    [Pg.178]    [Pg.156]    [Pg.6]    [Pg.244]    [Pg.91]    [Pg.580]    [Pg.2163]    [Pg.2219]    [Pg.2248]    [Pg.2248]    [Pg.2250]    [Pg.2251]    [Pg.2251]    [Pg.2252]    [Pg.1046]    [Pg.228]   
See also in sourсe #XX -- [ Pg.580 ]




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