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Loads single phase electrical

For example, a motor requiring 5 kW from the line is connected to the utility service entrance. If it has a power factor of 86%, the apparent power demanded by the load will be 5 kW divided by 86%, or more than 5.8 kW. The true power is 5 kW, and the apparent power is 5.8 kW. The same amount of work is being done by the motor, but the closer the power factor is to unity, the more efficient the system. To expand on this example, for a single-phase electric motor the actual power is the sum of several components, namely... [Pg.1179]

A single motor branch circuit is to be used to serve three motors rated at 1/3HP, 1/2HP, and 1/4HP. The motors are operating on a 115 volt, 60 hertz, single phase circuit. Using the given table, the calculated full load amps (A) that will be used to size the feeder for this branch circuit according to the National Electric Code is most nearly ... [Pg.22]

See other pages where Loads single phase electrical is mentioned: [Pg.1180]    [Pg.401]    [Pg.1]    [Pg.680]    [Pg.210]    [Pg.494]    [Pg.441]    [Pg.232]    [Pg.139]    [Pg.401]    [Pg.401]    [Pg.191]    [Pg.355]    [Pg.66]    [Pg.183]    [Pg.112]    [Pg.222]    [Pg.235]    [Pg.291]    [Pg.1095]    [Pg.397]    [Pg.1259]    [Pg.133]    [Pg.228]    [Pg.121]    [Pg.297]    [Pg.605]    [Pg.318]    [Pg.195]    [Pg.297]    [Pg.431]    [Pg.1534]    [Pg.437]    [Pg.454]    [Pg.74]    [Pg.187]    [Pg.377]    [Pg.118]    [Pg.183]    [Pg.344]    [Pg.324]   
See also in sourсe #XX -- [ Pg.494 ]



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