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Langmuir-Blodgett technique symmetry

Any surface or interface breaks the inversion symmetry and is therefore a possible source of second-order effects. Owing to their surface sensitivity, second-harmonic generation measurements have developed into a very useful tool for probing the orientation of organic molecules in well-structured monolayers, such as those obtainable by the Langmuir-Blodgett technique (see Table 6). The surface susceptibility may in general be written as... [Pg.437]

To measure the force between lipid layers, a lipid is chosen, which at a certain concentration and temperature range forms an L phase. The L phase is a regularly spaced stack of lamellar fluid bilayers separated by water. From a symmetry point of view, the L phase can be considered a smectic-A (SmA) liquid crystal. The mean repeat distance between lipid bilayers in the L phase is measured by X-ray diffraction versus an applied osmotic pressure. Direct experiments have been carried out with the surface force apparatus. Therefore, the bilayers are formed either by spontaneous vesicle fusion [1254-1256] or by depositing two subsequent monolayers with the Langmuir-Blodgett technique [1255, 1257]. Atomic force microscope experiments, which have been carried out between two bilayers formed by spontaneous vesicle fusion, confirmed earlier results [1258]. [Pg.317]

The Langmuir-Blodgett deposition technique shows excellent promise for the assembly of films with noncentrosymmetric ordering and Coo symmetry. A system that was reported recently (3i) is shown in Figure 6.11. In this system, monolayers of the hemicyanine dye and the nitrostilbene... [Pg.317]

However, organic polymers, being amorphous, do not show second-order NLO effects. In order to employ them in second-order NLO measurements a polar order is induced by an external means such as electric field poling process or the Langmuir-Blodgett (LB) technique. Poled polymers and the majority of the LB films possess Cocv symmetry. Therefore, the second-order optical susceptibility tensor for SHG has only three independent nonzero elements, namely, zS ZzM Under Klienman symmetry [9] conjecture... [Pg.798]


See other pages where Langmuir-Blodgett technique symmetry is mentioned: [Pg.47]    [Pg.411]    [Pg.423]    [Pg.75]    [Pg.201]    [Pg.93]    [Pg.1349]    [Pg.226]   
See also in sourсe #XX -- [ Pg.317 ]




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