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Kinetic energy lost from

The kinetic energy lost by the wall is equal to the kinetic energy gained by the bead. From Eq. (15.2)... [Pg.176]

Impact Resistance, Dart Drop The impact resistance is derived from the mass of the dart and the drop height that cause the specimen to crack or rupture. The total energy impact measures the kinetic energy lost by the free-falling dart that passes through the film. [Pg.197]

AWjond 12.5(a) condensation (b) fusion (c) vaporization 12.7 The gas molecules slow down as the gas is compressed. Therefore, much of the kinetic energy lost by the propane molecules is released to the surroundings. 12.11 At first, the vaporization of liquid molecules from the surface predominates, which increases the number of gas molecules and hence the... [Pg.820]

Figure 4-5 An orifice-type leak in a process vessel. The energy resulting from the pressure of the fluid height above the leak is converted to kinetic energy as the fluid exits through the hole. Some energy is lost because of frictional fluid flow. Figure 4-5 An orifice-type leak in a process vessel. The energy resulting from the pressure of the fluid height above the leak is converted to kinetic energy as the fluid exits through the hole. Some energy is lost because of frictional fluid flow.
KMT assumes that the gas particles neither attract nor repel each other. They may collide with each other, but if they do, it assumes the collisions are elastic—no kinetic energy is lost, only transferred from one gas molecule to another. [Pg.86]

In order to achieve breakdown, electrons (either from the air or from the body) must be accelerated to a sufficient velocity to ionize the air and breed more electrons by any one of several processes. In an actual gas, however, some of the kinetic energy of the electrons is lost in collisions with air molecules without resulting in ionization. This combined effect has been expressed in terms of the Townsend ionization coefficient. As a body becomes smaller, its curvature increases and the electric field intensity drops off more rapidly with distance from the surface consequently, to accelerate electrons a given amount, the body surface field intensity must be higher than for a flat surface. Actually, because of increased attenuation resulting from the increased distance that an electron must travel through air to achieve a given acceleration, the required surface intensity must increase even faster. [Pg.44]


See other pages where Kinetic energy lost from is mentioned: [Pg.1318]    [Pg.69]    [Pg.118]    [Pg.554]    [Pg.681]    [Pg.126]    [Pg.971]    [Pg.32]    [Pg.308]    [Pg.185]    [Pg.815]    [Pg.1318]    [Pg.69]    [Pg.222]    [Pg.17]    [Pg.88]    [Pg.286]    [Pg.815]    [Pg.133]    [Pg.205]    [Pg.306]    [Pg.389]    [Pg.95]    [Pg.151]    [Pg.788]    [Pg.72]    [Pg.413]    [Pg.268]    [Pg.900]    [Pg.40]    [Pg.282]    [Pg.25]    [Pg.159]    [Pg.28]    [Pg.87]    [Pg.27]    [Pg.434]    [Pg.339]    [Pg.121]    [Pg.66]    [Pg.40]    [Pg.120]   
See also in sourсe #XX -- [ Pg.376 ]

See also in sourсe #XX -- [ Pg.376 ]




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