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Half-integral

V l5ini7iand S = I, respectively.. STmist be positive and can assume either integral or half-integral values, and the quantum numbers lie in the mterval... [Pg.28]

Electrons, protons and neutrons and all other particles that have s = are known as fennions. Other particles are restricted to s = 0 or 1 and are known as bosons. There are thus profound differences in the quantum-mechanical properties of fennions and bosons, which have important implications in fields ranging from statistical mechanics to spectroscopic selection mles. It can be shown that the spin quantum number S associated with an even number of fennions must be integral, while that for an odd number of them must be half-integral. The resulting composite particles behave collectively like bosons and fennions, respectively, so the wavefunction synnnetry properties associated with bosons can be relevant in chemical physics. One prominent example is the treatment of nuclei, which are typically considered as composite particles rather than interacting protons and neutrons. Nuclei with even atomic number tlierefore behave like individual bosons and those with odd atomic number as fennions, a distinction that plays an important role in rotational spectroscopy of polyatomic molecules. [Pg.30]

Beeause Pij obeys Pij Pij = 1, the eigenvalues of the Pij operators must be +1 or -1. Eleetrons are Fermions (i.e., they have half-integral spin), and they have wavefunetions whieh are odd under permutation of any pair Pij P = - P. Bosons sueh as photons or deuterium nuelei (i.e., speeies with integral spin quantum numbers) have wavefunetions whieh obey Pij P = + P. [Pg.240]

Fermions are particles that have the properties of antisymmetry and a half-integral spin quantum number, among others. [Pg.258]

Iron is notable for the range of electronic spin states to which it gives rise. The values of S which are found include every integral and half-integral value from 0 to i.e. every value possible for a d-block element (Table 25.4). [Pg.1079]

Schwartz, H. M., Phys. Rev. 103, 110, "Ground state solution of the non-relativistic equation for He." More rapid convergence in the Ritz variational method by inclusion of half-integral powers in the Hylleraas function. [Pg.349]

ABSTRACT The statistical treatment of resonating covalent bonds in metals, previously applied to hypoelectronic metals, is extended to hyperelectronic metals and to metals with two kinds of bonds. The theory leads to half-integral values of the valence for hyperelectronic metallic elements. [Pg.407]

Because of the approximation of all of these values to z + 1/2, it is, we suggest, justified to assume the half-integral values of the valence of hyperelectronic metals, as was done in 1949 on an empirical basis (2). [Pg.407]

As a basis for subsequent discussion, we begin with a brief outline of relevant aspects of the normal n.m.r. experiment in which an assembly of nuclei with half-integral spins is observed (for a fuller treatment of the basic principles of magnetic resonance, see e.g. Carrington and MoLaohlan, 1967). [Pg.54]

Introduction of the half-integral spin of the electrons (values h/2 and —fe/2) alters the above discussion only in that a spin coordinate must now be added to the wavefunctions which would then have both space and spin components. This creates four vectors (three space and one spin component). Application of the Pauli exclusion principle, which states that all wavefunctions must be antisymmetric in space and spin coordinates for all pairs of electrons, again results in the T-state being of lower energy [equations (9) and (10)]. [Pg.63]

The wave fiinetion for a system of N identical particles is either symmetric or antisymmetric with respect to the interchange of any pair of the N particles. Elementary or eomposite particles with integral spins (s = 0, 1,2,. ..) possess symmetrie wave functions, while those with half-integral spins (s = 1. .)... [Pg.217]

Figure 6.8 shows the Bjerrum plots for an weak acid (benzoic acid, pKa 3.98, log So — 1.55, log mol/L [474]), a weak base (benzydamine, pKa 9.26, log So —3.83, log mol/L [472]), and an ampholyte (acyclovir, pKa 2.34 and 9.23, log So — 2.16, log mol/L I/40N ). These plots reveal the pKa and pA pp values as the pcH values at half-integral % positions. By simple inspection of the dashed curves in Fig. 6.8, the pKa values of the benzoic acid, benzydamine, and acyclovir are 4.0, 9.3, and (2.3, 9.2), respectively. The pA pp values depend on the concentrations used, as is evident in Fig. 6.8. It would not have been possible to deduce the constants by simple inspection of the titration curves (pH vs. volume of titrant, as in Fig. 6.7). The difference between pKa and pA pp can be used to determine log So, the intrinsic solubility, or log Ksp, the solubility product of the salt, as will be shown below. Figure 6.8 shows the Bjerrum plots for an weak acid (benzoic acid, pKa 3.98, log So — 1.55, log mol/L [474]), a weak base (benzydamine, pKa 9.26, log So —3.83, log mol/L [472]), and an ampholyte (acyclovir, pKa 2.34 and 9.23, log So — 2.16, log mol/L I/40N ). These plots reveal the pKa and pA pp values as the pcH values at half-integral % positions. By simple inspection of the dashed curves in Fig. 6.8, the pKa values of the benzoic acid, benzydamine, and acyclovir are 4.0, 9.3, and (2.3, 9.2), respectively. The pA pp values depend on the concentrations used, as is evident in Fig. 6.8. It would not have been possible to deduce the constants by simple inspection of the titration curves (pH vs. volume of titrant, as in Fig. 6.7). The difference between pKa and pA pp can be used to determine log So, the intrinsic solubility, or log Ksp, the solubility product of the salt, as will be shown below.
B) Is there a central line If there is no central line, then there must be an even number of lines, which suggests an odd number of half-integer nuclei i.e., I = 1/2, 3/2, etc.), which would cause splitting of any center line arising from an even number of half-integral nuclei or any number of nuclei with integer spin (I = 1,2, etc). [Pg.33]

In the free electron model, the electrons are presumed to be loosely bound to the atoms, making them free to move throughout the metal. The development of this model requires the use of quantum statistics that apply to particles (such as electrons) that have half integral spin. These particles, known as fermions, obey the Pauli exclusion principle. In a metal, the electrons are treated as if they were particles in a three-dimensional box represented by the surfaces of the metal. For such a system when considering a cubic box, the energy of a particle is given by... [Pg.358]

Schrodinger s equation has solutions characterized by three quantum numbers only, whereas electron spin appears naturally as a solution of Dirac s relativistic equation. As a consequence it is often stated that spin is a relativistic effect. However, the fact that half-integral angular momentum states, predicted by the ladder-operator method, are compatible with non-relativistic systems, refutes this conclusion. The non-appearance of electron... [Pg.237]

There is no theoretical ground for this conclusion, which is a purely empirical result based on a variety of experimental measurements. However, it seems to apply everywhere and to represent a law of Nature, stating that systems consisting of more than one particle of half-integral spin are always represented by anti-symmetric wave functions. It is noted that if the space function is symmetrical, the spin function must be anti-symmetrical to give an anti-symmetrical product. When each of the three symmetrical states is combined with the anti-symmetrical space function this produces what is... [Pg.244]

Electrons with their half-integral spins are known as Fermi particles or fermions and no more than two electrons can occupy a quantum state. At absolute zero the electrons occupy energy levels from zero to a maximum value of f F, defined by... [Pg.305]

After values of a and are assumed, this equation can be integrated either analytically or numerically over the time ranges of the data. If the values of the k s are substantially constant, the correct choices of a and had been made. It is usual in this method to try only Integral or half integral values of the exponents, starting with the assumption that the rate equation conforms to the stoichiometry. [Pg.107]

This is solvable for 73 analytically for some half-integral values of n as tabulated, and numerically in general as shown on the graph. The plots show that multiple values are obtained for n = -0.5 and that a limiting value 9 = 2 is reached when n = -1. [Pg.764]


See other pages where Half-integral is mentioned: [Pg.172]    [Pg.176]    [Pg.381]    [Pg.1548]    [Pg.2076]    [Pg.18]    [Pg.461]    [Pg.202]    [Pg.675]    [Pg.57]    [Pg.137]    [Pg.23]    [Pg.56]    [Pg.93]    [Pg.226]    [Pg.66]    [Pg.272]    [Pg.122]    [Pg.18]    [Pg.236]    [Pg.236]    [Pg.242]    [Pg.288]    [Pg.467]    [Pg.75]    [Pg.396]    [Pg.399]    [Pg.242]    [Pg.343]    [Pg.343]   
See also in sourсe #XX -- [ Pg.343 ]

See also in sourсe #XX -- [ Pg.168 ]




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