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Group, Abelian cyclic

This group of order g is a cyclic group. Any cyclic group is Abelian. Further, if g is prime any group of order g is cyclic. [Pg.91]

Then C I+1=C, CA+2=C2, etc., and if h is the smallest integer for which (2) holds, there are only h different powers of C. The element C satisfying (2) is said to be of the order h, and a collection of all powers of C is a group of order h a group composed of powers of a single element is called a cyclic group. All cyclic groups are Abelian but the converse is not true. Since ... [Pg.407]

By contrast, not all abelian groups are cyclic. A simple example is the groups D2 of order 4, which is presented in Table 3.3. It needs two perpendicular twofold axes as generators and thus cannot be cyclic. Nonetheless, it is abelian since its generators commute. [Pg.27]

Moreover, thanks to the symmetry operations cyclicality from the pure subgroups of the rotations Cy that will be called cyclic group. Any cyclic group is abelian, natural property derived from the of the group objects nature only rotations, by their nature commutative. [Pg.132]

We will first consider an abelian group, namely the cyclic group Zra. The pi s forming a regular representation commute with each other and... [Pg.90]

Let us consider now the cases where the only symmetry element is a proper axis, C . This generates a set of operations C , CJ, Cj,.. . , Cna = E. Hence a molecule with C as its only symmetry element would belong to a group of order , which is designated C . It may be noted that a C group is a cyclic group (see Section 2.2) and hence also Abelian. [Pg.41]

As noted earlier, a cyclic group is Abelian, and each of its h elements is in a separate class. Therefore, it must have h one-dimensional irreducible representations. To obtain these there is a perfectly general scheme which is perhaps best explained by an example. It will be evident that the example may be generalized. Let us consider the group C5, consisting of the five commuting operations C5, C, C, C5, E we seek a set of five one-... [Pg.95]

Clearly, this set forms a group Qe of order six the group is neither Abelian nor cyclic. A group with the same multiplication table as Q (perhaps to within a permutation of rows and columns) is said to be isomorphic to Q. ... [Pg.92]

Exercise 1.1-2 (a) Show that cyclic groups are Abelian, (b) Show that for a finite cyclic group the existence of the inverse of each element is guaranteed, (c) Show that uj cxp( 2n /n) generates a cyclic group of order n, when binary composition is defined to be the multiplication of complex numbers. [Pg.3]

Any cyclic group G is isomorphic to the additive group of integers modulo IGI. For any generator g, the exponentiation function expgix) = g is an isomorphism into G. The inverse is the discrete-logarithm function logg. In particular, G is Abelian, i.e., commutative. [Pg.213]

The use of symmetry—at least the translational subgroup—is essential to modem first-principles calculations on crystalline solids. Group theory is simplest for Abelian groups such as the translational subgroup of a crystal or the six-fold-rotational subgroup of the benzene molecule. For such simple cyclic groups, the irreducible representations are characterized by a phase, exp(ifc), associated with each step in a direction of periodicity. For one-dimensional (or cyclic) periodicity,... [Pg.153]

A mirror plane and a twofold (or any even order) axis perpendicular to the plane generates an inversion center (Fig. 2U4or Fig. 2.13(c) with 0 = 90°). Two of these three elements generate the smallest non-cyclic (but Abelian) group this is a group of order 4 which comprises the operations E, A2J1, and I2. [Pg.44]

Every finitely generated abelian group can be written as a direct product of cyclic groups of prime-power order with a finite number of infinite cyclic groups. In this presentation, the summands are uniquely determined up to isomorphism and order. [Pg.44]

Consequently, the products [Pi][P2] and [P2][PlJ represent two different reaction mechanisms, hence the group is not commutative. However, every nontrivial fundamental group III always contains a special Abelian subgroup, the infinite cyclic group. Of course, in the case of m=0 the group is also commutative, since then... [Pg.30]

C a unique symmetry axis of order n these are cyclic abelian groups. [Pg.405]


See other pages where Group, Abelian cyclic is mentioned: [Pg.10]    [Pg.53]    [Pg.10]    [Pg.53]    [Pg.407]    [Pg.41]    [Pg.2904]    [Pg.2918]    [Pg.92]    [Pg.88]    [Pg.561]    [Pg.86]    [Pg.336]    [Pg.4753]    [Pg.324]    [Pg.26]    [Pg.525]    [Pg.186]    [Pg.27]    [Pg.447]    [Pg.525]    [Pg.51]   
See also in sourсe #XX -- [ Pg.10 ]

See also in sourсe #XX -- [ Pg.10 ]




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