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Glucose open-chain forms

In the cyclization of the open-chain form of glucose to form the stable hemiacetal, it may be difficult to work out what has happened. Number the carbon atoms in the open-chain form and put the same numbers on the hemiacetal so that you can see where each carbon atom has gone. Then draw a mechanism for the reaction, glucose open-chain form cyclic form... [Pg.358]

A6-Tctra-0-mcthyl-D-glucose Open-chain form... [Pg.1102]

It is to be expected, on these grounds, that the predominating component of the mutarotation equilibrium of 3,6-anhydro-glucose will be 3,6-anhydro-glucofuranose whereas that of 3,6-anhydro-galactose will be the open-chain form. Neither will include pyranose forms. [Pg.77]

Figure 4.17 The trioses D-glyceraldehyde (aldose) and dihydroxyacetone (ketose), the pentose D-ribose, the hexoses D-galactose and D-glucose (aldoses) and the ketohexose D-fructose in their open chain forms. The configuration of the asymmetrical hydroxyl group on the carbon, the furthest away from the aldehyde or ketone group, determines the assignment of D- or L-configuration. Figure 4.17 The trioses D-glyceraldehyde (aldose) and dihydroxyacetone (ketose), the pentose D-ribose, the hexoses D-galactose and D-glucose (aldoses) and the ketohexose D-fructose in their open chain forms. The configuration of the asymmetrical hydroxyl group on the carbon, the furthest away from the aldehyde or ketone group, determines the assignment of D- or L-configuration.
Monosaccharide structures may be depicted in open-chain forms showing their carbonyl character, or in cyclic hemiacetal or hemiketal forms. Alongside the Fischer projections of glucose, ribose, and fructose shown earlier, we included an alternative... [Pg.468]

We should first consider the open-chain form of glucose 6-phosphate, rather than its pyranose hemiacetal form (see Section 12.2.1). The open-chain aldose has the requirements for enolization, namely a hydrogen a to the aldehyde carbonyl group. Enolization produces in this case an enediol, which can revert to a keto form in two ways, i.e. reforming... [Pg.580]

In the case of the oximes of the aldose sugars, the situation is more complicated because of the possibility of both open-chain and cyclic structures. That aldose oximes can react in the open-chain form follows from the formation of the nitriles and from the isolation of acylated open-chain aldose oximes as secondary products in preparation of nitriles. For example, Wolfrom and Thompson, by the action of sodium acetate-acetic anhydride on n-glucose oxime, not only obtained pentaacetyl-D-glucononitrile, in 40% yield, but also isolated a small amount of hexaacetyl-oWeAydo-D-glucose oxime (V) identical with that prepared by mild acetylation of pentaacetyl-aWe%do-D-glucose oxime (IV) whose structure was assured by its formation from pentaacetyl-aldehydo-D-glucoae (III). [Pg.121]

The two most common functional groups found in monosaccharides (in open chain form) are aldehyde and ketone. When a monosaccharide contains an aldehyde, it is known as an aldose, e.g. glucose, and in the case of ketone, it is called a ketose or keto sugar, e.g. fructose. [Pg.304]

D-Glucose in open chain form D-Giucitoi or D-sorbitoi, an aiditoi... [Pg.308]

Sucrose is a disaccharide that is composed of a unit of glucose (acetal form) and a unit of fructose (ketal form) linked through C-1 of glucose and C-2 of fructose, i.e. a 1,2 link. In sucrose, neither glucose nor fructose can exist in open chain form because of the formation of acetal and ketal as shown below. As a result, sucrose is not a reducing sugar, and does now exhibit mutarotation. The specific rotation [a]D of sucrose is +66°. [Pg.313]

The rapid spontaneous mutarotation of glucose-6-phosphate has been shown to result from an intramolecular catalysis of the reaction by the phosphate group at carbon 6 (81). The cleavage of glucose into three carbon fragments, which is essentially a reversal of the aldol condensation reaction, requires the ketohexose as substrate. The necessary isomerization reaction to form the ketohexose then uses the open-chain form intermediate of the mutarotation reaction. Salas et al. (80) have speculated that the enhanced mutarotation of glucose-6-phosphate may thus have been the key requirement which led to the evolution of the phosphorolytic pathway for glucose metabolism. [Pg.297]

Order the following substances from the least to most oxidized carbon Formaldehyde, carbon dioxide, methane, formic acid, methanol. Use the open-chain form of glucose and the structural formula for decanoic acid and this scheme to determine the aver-... [Pg.434]


See other pages where Glucose open-chain forms is mentioned: [Pg.189]    [Pg.341]    [Pg.98]    [Pg.358]    [Pg.1362]    [Pg.358]    [Pg.1362]    [Pg.274]    [Pg.138]    [Pg.44]    [Pg.411]    [Pg.496]    [Pg.1362]    [Pg.448]    [Pg.533]    [Pg.1144]    [Pg.991]    [Pg.1013]    [Pg.189]    [Pg.341]    [Pg.98]    [Pg.358]    [Pg.1362]    [Pg.358]    [Pg.1362]    [Pg.274]    [Pg.138]    [Pg.44]    [Pg.411]    [Pg.496]    [Pg.1362]    [Pg.448]    [Pg.533]    [Pg.1144]    [Pg.991]    [Pg.1013]    [Pg.1040]    [Pg.1057]    [Pg.1040]    [Pg.1057]    [Pg.616]    [Pg.1145]    [Pg.146]    [Pg.171]    [Pg.47]    [Pg.34]    [Pg.35]    [Pg.282]    [Pg.494]    [Pg.309]    [Pg.312]    [Pg.245]    [Pg.1047]    [Pg.1064]    [Pg.295]    [Pg.1049]   
See also in sourсe #XX -- [ Pg.307 ]




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Glucose chain

Open form

Open-chain

Open-chain form of glucose

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