Fsolve

Matlab does not include a routine of the kind of fzero for more than one variable. Only the function fsolve, which is part of the Optimisation Toolbox, can deal with systems of equations with several variables. Here we demonstrate the application of fsolve to the system of equations (3.70). [Pg.75]

It is possible to adapt fsolve to analyse equilibrium problems for which we developed NewtonRaphson. m. Attempts to do so are frustrated by the slow computation times, compared with NewtonRaphson. m. The reason lies in the fact that fsolve is a very general program that can deal with anything, while NewtonRaphson. m is dedicated to one specific task. Usually small, dedicated programs execute faster but are not easily adapted for other tasks. [Pg.76]

It is quite easy to use the fsolve function in Matlab to solve for the four unknowns. Figure 2.14 gives a program that solves for the four reactor compositions given reactor temperature, reactor volume, feed conditions and kinetics. [Pg.53]

Uses fsolve to find steady-state composition of reversible reaction in a h CSTR of volume vr at temperature tr... [Pg.53]

Use fsolve to find solution of 4 nonlinear algebraic equations %... [Pg.53]

H Uses fsolve to find steady-atate compositions of consecutive reactions ((49.3e-6)/ltratlo) exp(139.4e6/8314/333)... [Pg.57]

One can solve equations in Maple using the solve and fsolve commands. The solve command is used to solve linear equations in symbolic form and the fsolve command is used to solve linear and nonlinear equations numerically. For example,... [Pg.6]

One can use the fsolve command in Maple to solve equations numerically ... [Pg.6]

Note that fsolve returns a floating point number with a decimal point. [Pg.6]

Two or more nonlinear equations can be solved by using fsolve . For example, consider finding the solutions (x and y) for the following two equations. [Pg.7]

Use Maple to solve the following equations numerically by using fsolve . Find all the possible roots. [Pg.26]

Next, the time taken to reach 99% of this steady state value is determined by using fsolve to find the time T when TT3 is 99% of it steady state value. First, define eq3 ... [Pg.54]

The solve command takes too long to solve and gives complex roots. Hence, the fsolve command is used to solve for the real values. [Pg.220]

For higher values of <, fsolve produces only the correct solution > cc2[2] =fsolve(subs(Phi=1, eqc),c1=1) ... [Pg.222]

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