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Equivalent diameter, mineral particle

Mineral particles (density of 2800 kg/m and equivalent diameter of 5p,m) are all separated from water at a volumetric rate of 0.25 m /sec. What corresponding size cut will result for a suspension of coal particles (density of coal of 1300 kg/m ) in oil (density of 850 kg/m, viscosity of 0.01 N sec/m) Assume Stokes Law holds. [Pg.403]

In a test on a centrifuge all particles of a mineral of density 2800 kg/m3 and of size 5 xm, equivalent spherical diameter, were separated from suspension in water fed at a volumetric throughput rate of 0.25 m3/s. Calculate the value of the capacity factor E. [Pg.482]

Figure 2. Distribution of selected minerals in Upper Freeport coal as a function of area-equivalent particle diameter (ym). Figure 2. Distribution of selected minerals in Upper Freeport coal as a function of area-equivalent particle diameter (ym).

See other pages where Equivalent diameter, mineral particle is mentioned: [Pg.565]    [Pg.452]    [Pg.180]    [Pg.9]    [Pg.581]    [Pg.431]    [Pg.301]    [Pg.3018]    [Pg.511]    [Pg.394]    [Pg.168]    [Pg.479]    [Pg.131]    [Pg.923]    [Pg.123]   
See also in sourсe #XX -- [ Pg.125 ]




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