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Engineering shear strain

F(FG = normal (shear) component of force A = area u(w) = normal (shear) component of displacement o-(e ) = true tensile stress (nominal tensile strain) t(7) = true shear stress (true engineering shear strain) p(A) = external pressure (dilatation) v = Poisson s ratio = Young s modulus G = shear modulus K = bulk modulus. [Pg.298]

Note that Y represents engineering shear strain whereas (l ) represents tensor shear strain. [Pg.56]

Figure 2-3 Engineering Shear Strain versus Tensor Shear Strain... Figure 2-3 Engineering Shear Strain versus Tensor Shear Strain...
The shear modulus n is defined as the ratio of shear stress to engineering shear strain on the loading plane. [Pg.97]

The engineering shear strain = shear strain in the y Oz plane. In contrast, the shear strain e y is the average of the shear strain on the y Oz face along the y direction, and on the xOz face along the X direction. [Pg.97]

Recall that the engineering shear strain was previously given as yij = 2sij. The above stress may also be expressed as being a reverse relation ... [Pg.58]

The symbol I represents the strain invariants analogous to the stress invariants given as J in Eqs. (1.22e) and (1.23). The coefficients in Eq. (1.98c) are the results of the engineering shear strain being ... [Pg.64]

The authors [6] suggest the term shearability , Sm, for the maximum shear strain that a homogeneous crystal can withstand. It is defined by Sm = argmax o-(s), where a(s), is the resolved shear stress and s is the engineering shear strain in a specified slip system. The relaxed shear stress, (7 in Table 4.2 is normalized by Gr. In this table, experimental and calculated values of the relaxed shear vales of Gr are given. For details on these calculations, refer to the work of Ogata et al. [6]. [Pg.298]

Here we have used the engineering shear strain yxy = 2sxy. The representation of stress and strain given by (2.215) is referred to as the contracted form. [Pg.52]

In equation (3.1) G is the elastic shear modulus and y is one-half the engineering shear strain. This depicts a material for which the stress is proportional to the tensorial strain even though a plastic strain results in the vicinity of an indenter. [Pg.43]

Explain the difference between engineering shear strain and the ten-sorial alternative. [Pg.53]

So the infinitesimal strain tensor is established as a symmetric tensor of second order. With provision for the engineering shear-strain measures aside the diagonal, the components can be assigned as given by the left-hand side of Eqs. (3.20). An alternative representation may be gained by resorting the six independent components into a vector as shown on the right-hand side of Eqs. (3.20) ... [Pg.26]

As visible on the right-hand side of Eqs. (3.22), the transformation of strains does not yet cope with the engineering shear-strain measures introduced in the previous subsection. This can be accomplished, as shown for the planar case by Jones [107], by multiphcation with the correction matrix R ... [Pg.28]


See other pages where Engineering shear strain is mentioned: [Pg.31]    [Pg.298]    [Pg.57]    [Pg.57]    [Pg.75]    [Pg.1161]    [Pg.30]    [Pg.937]    [Pg.45]    [Pg.21]    [Pg.342]    [Pg.169]    [Pg.119]    [Pg.27]    [Pg.5]    [Pg.534]    [Pg.536]    [Pg.32]   
See also in sourсe #XX -- [ Pg.52 ]




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