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Eigenfunctions lowest-energy

The value o+l <0.4 found for H2 shows that even in the lowest state the molecules are rotating freely, the intermolecular forces producing only small perturbations from uniform rotation. Indeed, the estimated (3vq<135° corresponds to Fo <28 k, which is small compared with the energy difference 164 k of the rotational states j = 0 and j= 1, giving the frequency with which the molecule in either state reverses its orientation. The perturbation treatment shows that with this value of Fo the eigenfunctions and energy levels in all states closely approximate those for the free spatial rotator.9... [Pg.790]

Recall that the minimum requirement for a many-electron wave function is that it be written as a suitably antisymmetrized sum of products of one-electron wave functions, that is, as a Slater determinant of MOs [see equation (A.68)] In Chapter 2 and Appendix A, we find that the condition that this be the best possible wave function of this form is that the MOs be eigenfunctions of a one-electron operator, the Fock operator [recall equation (A.42)], from which one can choose the appropriate number of the lowest energy. The Fock operator in restricted form, F( 1) [RHF, the UHF form was given in equation (A.41)], is given by... [Pg.34]

In summary, to obtain a many-electron wave function of the single determinantal form [equation (A.12)] which will give the lowest electronic energy [equation (A.14) or (A.27)], one must use one-electron wave functions (orbitals) which are eigenfunctions of the one-electron Fock operator according to equation (A.42). There are many, possibly an infinite number of, solutions to equation (A.42). We need the lowest Ne of them, one for each electron, for equation (A. 12) [or (A.27)]. When the Ne MOs of lowest energy satisfy equation (A.42), then Eq=Ehf [equation (A.27)] and o= hf [equation (A.12)]. [Pg.229]

The dominant error term is third order in At. The initial wavefunction (Qx,Qy,t) at t = 0 is normally the lowest energy eigenfunction of the initial state of the spectroscopic transition. The value of the wavefunction at incremental time intervals At is calculated by using Eq. (7) for each point on the (Qx,Qy) grid. The autocorrelation function is then calculated at each time interval and the resulting < (t> is Fourier transformed according to Eq. (2) to give the emission spectrum. [Pg.179]

The DMC method achieves the lowest-energy eigenfunction by employing the quantum mechanical evolution operator in imaginary time [25], For an initial function expanded in eigenstates, one finds that contributions of the excited states decay exponentially fast with respect to the ground state. [Pg.318]

A wave function of an electron configuration is generally approximated as a product of molecular orbital functions, which are eigenfunctions of a one-electron Hamilton operator. When 2n electrons occupy n molecular orbitals, the wave function of electron configuration of the lowest energy is written as... [Pg.269]

The lowest-energy solutions deviating from spherieal symmetry are the 2p-orbitals. Using Eqs (7.44), (7.45) and the f = 1 spherical harmonics, we find three degenerate eigenfunctions ... [Pg.58]

The usefulness of this method is that we can calculate energies from a variety of functions, and we know that the lowest energy obtained is closest to the truth. More systematically, we can express a trial eigenfunction as a function of certain variables and calculate the energy from equation (1.32) as a function of these variables. The energy can be minimized with respect to these variables, and we will then have obtained the best energy value from this type of function. [Pg.24]

Since the reference system s consists of noninteracting particles, the results of Section 6.2 and the Pauli principle show that the ground-state wave function of the reference system is the antisymmetrized product (Slater determinant) of the lowest-energy Kohn-Sham spin-orbitals up of the reference system, where the spatial part 0P(r,) of each spin-orbital is an eigenfunction of the one-electron operator AP that is. [Pg.577]

For linear systems, the situation is simple. There are no degeneracies (Equation 3.38). Equation (3.39) shows that the eigenfunction with the lowest energy is symmetric at reflection in a plane through the center of the molecule, perpendicular to the molecular axis. The next are alternatingly antisymmetric and symmetric. The transition density for the HOMO LUMO transition has to be antisymmetric. If the... [Pg.104]

A serious deficiency is that neither a Hartree product nor a Slater determinant can be an eigenfunction of the fV-electron Hamilton operator. Therefore cannot be a solution of the time-independent electronic Schrodinger equation. The reason is that the A-electron Hamiltonian cannot be written as a sum of N one-electron Hamiltonians, due to the repulsive Coulomb interactions between the electrons. Nevertheless, in practice it turns out that we can work rather well with an approximate wave function consisting of only one Slater determinant if we choose that particular Slater determinant that yields the lowest energy expectation value 7 ). In other words, we must vary the spin orbitals in P until we have reached the lowest value... [Pg.3]


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See also in sourсe #XX -- [ Pg.190 ]




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