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Echelon form

A system of equations where the first unknown is missing from all subsequent equations and the second unknown is missing from all subsequent equations is said to be in echelon form. Every set or equation system comprised of linear equations can be brought into echelon form by using elementary algebraic operations. The use of augmented matrices can accomplish the task of solving the equation system just illustrated. [Pg.14]

The echelon form of the equations can also be put into matrix form as follows. Echelon form ... [Pg.15]

The first (preceding) matrix is reduced to echelon form (zeros in the first and the second rows of column one) by... [Pg.20]

In this case, A can be transformed by elementary row operations (multiply the second row by 1/2 and subtract the first row from the result) to the unit-matrix or reduced I0W-echelon form ... [Pg.8]

The system of equations (2.12) can be written using the column echelon form of matrix M as follows ... [Pg.34]

The rank of matrix M is 7. As the system is rank deficient, it admits a decomposition into two subsystems, one estimable and the other nonestimable. To determine which variables are observable, the column echelon form of M is obtained and T l... [Pg.34]

From the decomposition of M into its column echelon form, it can be seen that fa is nonestimable. The inspection of T 1 indicates that fa is also nonestimable, because its calculation depends on fa. [Pg.35]

The utility of matrices in the applied sciences is, in many cases, connected with the fact that they provide a convenient method for the formulation of physical problems in terms of a set of equations. It is therefore important to become familiar with the manipulation of the equations, or equivalently with the manipulation of rows and columns of the corresponding matrix. First, we will be concerned with some basic tools such as column-echelon form and elementary matrices. Let us introduce some definitions (Noble, 1969). [Pg.40]

The last (m - k) columns of a column-echelon form are zero. The first k columns of the column echelon form are nonzero. [Pg.40]

Although there is a considerable degree of freedom in the sequence of calculations, when reducing a matrix to a column-echelon form, this is unique and the rank of the matrix is equal to the number of nonzero columns in the column echelon. [Pg.40]

If G is an (m x g) matrix of rank k and Ug denotes the column-echelon form of G, then a nonsingular matrix Eq exists such that... [Pg.41]

The column-echelon form of G is obtained by performing a sequence of elementary column operations on this matrix. This means that we can find a sequence of elementary matrices EpEp i... Ei corresponding to the elementary column operations, such that... [Pg.41]

Also, (2) follows immediately since the column-echelon form of a nonsingular matrix is the unit matrix. ... [Pg.41]

The row operations (a) to (c) are performed on (A b) until the front m by n matrix A achieves row echelon form. In a row echelon form R of A each row has a first nonzero entry, called a pivot, that is further to the right than the leading nonzero entry (pivot) of any previous row, or it is the zero row. [Pg.538]

When the matrix is reduced to echelon form by Gauss-Jordan elimination, the rank of the matrix can be shown to be equal to 3. With n = 5, the number of independent reactions is 5 - 3 = 2. Equation (4.575) requires that, for each of the two independent reactions,... [Pg.390]

For the identifiable parameters, we should obtain for solutions, = 0. For the nonidentifiable parameters there should not be such unique solutions. To check that, use row reduction to row echelon form, with pivoting on maximum elements. When completed, the equations should have the following form. [Pg.320]

The rank of a matrix A is the number of nonzero rows in the reduced row echelon form of A. [Pg.391]

Of course, first we need to find an initial minimal DD pair. Following the null space approach [23, 24], we compute a basis of the kernel of the stoichiometric matrix S. More specifically, we compute a column-reduced echelon form of the basis and (after a permutation of rows) obtain... [Pg.791]

This is a system of three equations in three unknowns (Xj, X2, and X3), which can be solved by standard methods. Let us perform row operations on the above system to make the solution easier to interpret. Hence, performing elementary row operations and reducing the system to only elements on the main diagonal (also known as reduced row echelon form) gives... [Pg.153]

A is a 3 X 5 matrix and thus the null space of A will be a two-dimensional subspace in c -Cb-Cc-Cd-Ce space (the size of matrix N must he nx(n- d), or 5x2). To compute the null space of this matrix, we can reduce A to reduced row echelon form by performing elementary row operations on A, and determine all of the vectors in the null space (similar in procedure to that shown in Example 3). Hence reducing A to the equivalent matrix gives ... [Pg.174]

The matrix U has rank r, so there will be r basic variables and (n - r) free variables in the solution for h. In fact, we may further reduce the system in Equation 5.72 into row-reduced echelon form as follows ... [Pg.95]

Note that permutations of the columns of U may be necessary to obtain the row-reduced echelon form shown in Equation 5.73. Of course, in order to maintain consistency in the equations, column permutations in U must be accompanied by corresponding row permutations in h =. [Pg.95]


See other pages where Echelon form is mentioned: [Pg.41]    [Pg.18]    [Pg.22]    [Pg.539]    [Pg.22]    [Pg.390]    [Pg.157]    [Pg.95]    [Pg.95]    [Pg.361]    [Pg.361]   
See also in sourсe #XX -- [ Pg.14 , Pg.15 , Pg.20 ]

See also in sourсe #XX -- [ Pg.14 , Pg.15 , Pg.20 ]

See also in sourсe #XX -- [ Pg.95 ]




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