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E Oxidation Numbers

Because the sum of the oxidation numbers of the atoms in a compoimd must satisfy Rule 6 or 7 of the guidelines on the previous page, it is often possible to assign oxidation numbers when they are not known. This is illustrated in Sample Problem E. [Pg.221]

Sample Problem E Assign oxidation numbers to each atom in the following compounds or ions  [Pg.221]

Multiply known oxidation numbers by the appropriate number of atoms, and place the totals underneath the corresponding elements. There are six fluorine atoms, 6 X — 1 = — 6. [Pg.221]

The compoimd UFg is molecular. According to the guidelines, the sum of the oxidation numbers must equal zero. The total of positive oxidation numbers is therefore -F6. [Pg.221]

Divide the total calculated oxidation number by the appropriate number of atoms. There is only one uranium atom in the molecule, so it must have an oxidation number of +6. [Pg.221]


A half-reaction in which the oxidation number of an element is increased. Examples 2 Mg(s) + 02(g) — 2MgO(s) (2, 3) Mg(s) - Mg2+(s) + 2 e. oxidation number The effective charge on an atom in a compound, calculated according to a set of rules (see Toolbox K.l). An increase in oxidation number corresponds to oxidation a decrease corresponds to reduction. [Pg.960]


See other pages where E Oxidation Numbers is mentioned: [Pg.18]    [Pg.402]   


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