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Copper ionization energy

Penning ionization (plasma) The ionization of an atom by collision with a metastable atom in an excited state that is of higher energy than the ionization energy of the first atom. Example Ionization of copper (ionization energy = 7.86 eV) by excited argon (metastable excited states of 11.55 and 11.75 eV). [Pg.669]

The ionization energy is normally expressed in electronvolts (eV) for a single atom or in kilojoules per mole of atoms (kj-mol" 1). The first ionization energy, /j, is the energy needed to remove an electron from a neutral atom in the gas phase. For example, for copper,... [Pg.167]

Identify the element with the higher first ionization energy in each of the following pairs (a) iron and nickel (b) nickel and copper (c) osmium and platinum (d) nickel and palladium ... [Pg.813]

The enthalpy of atomization of copper does not differ at all for the two compounds, and the atomization of chlorine adds only a small difference for the second mole of chlorine. The major energy cost for CuCl2 is the second ionization energy of copper which is compensated by the electron affinity to form the second chloride ion and especially the lattice energy. Since the electron ionized to form Cu2 is a d electron and does not break a noble gas structure, IE2 is not excessive, and both CuCl and CuCl2 are stable compounds. [Pg.67]

The second ionization energy, of an element is the energy needed to remove an electron from a singly charged gas-phase cation. For copper,... [Pg.185]

The low ionization energies of elements at the lower left of the periodic table account for their metallic character. A block of metal consists of a collection of cations of the element surrounded by a sea of valence electrons that the atoms have lost (Fig. 1.42). For example, a piece of copper consists of a stack of Cu+ ions held together by a sea of electrons, each of which comes from one of the atoms in the sample. Only elements with low ionization energies—the members of the s block, the d block, the f block, and the lower left of the p block—can form metallic solids, because only they can lose electrons easily. [Pg.187]

When a d-metal atom loses electrons to form a cation, it first loses its outer s-electrons. However, most transition metals form ions with different oxidation states, because the d-electrons have similar energies and a variable number can also be lost when they form compounds. Iron, for instance, forms Fe2+ and Fe3+ copper forms Cuf and Cu2+. The reason for the difference between copper and potassium, which forms only K+, can be seen by comparing their second ionization energies, which are 1958 kj-mol 1 and 3051 kj-mol-1, respectively. To form Cu2+, an electron is removed from the d subshell of [Ar]3d10 but to form K2+, the electron would have to be removed from potassium s argonlike core. Because such huge amounts of energy are not readily available in chemical reactions, a potassium atom can lose only its 4s-electron. [Pg.192]

These points are well illustrated by comparing Cu, Ag and Au with respect to the relative stabilities of their oxidation states. Although few compounds formed by these elements can properly be described as ionic, the model can quite successfully rationalise the basic facts. The copper Group 1 Id is perhaps the untidiest in the Periodic Table. For Cu, II is the most common oxidation state Cu(I) compounds are quite numerous but have some tendency towards oxidation or disproportionation, and Cu(III) compounds are rare, being easily reduced. With silver, I is the dominant oxidation state the II oxidation state tends to disproportionate to I and III. For gold, III is the dominant state I tends to disproportionate and II is very rare. No clear trend can be discerned. The relevant quantities are the ionization energies Iu l2 and A the atomisation enthalpies of the metallic substances and the relative sizes of the atoms and their cations. These are collected below / and the atomisation enthalpies AH%tom are in kJ mol-1 and r, the metallic radii, are in pm. [Pg.154]

Instead the critical factor is the overlap between cluster orbital of the same symmetry. In particular for on-top dissociation, a requirement of the on-top atom is an easily accessible atomic state with singly occupied 3d and 4s orbitals (5-7). When this condition is fulfilled, the on-top dissociation becomes the most favorable pathway. This is the reason why nickel succeeds and copper fails to break the H bond (7,8). The correlation between the ionization energies and the reactivities of the clusters is therefore, in our opinion, the most surprising of all the above mentioned experimental results. [Pg.126]

The increased ionization energies of the heavier transition metals should not be unexpected by anyone who has had a modicum of laboratory experience with any of these elements. Although none of the coinage metals is very reactive, gold has a well-deserved reputation for being less reactive than copper or silver iron, cobalt, and nickel rust and corrode, but osmium, indium, and platinum are noble and unreaclive and therefore are used in jewelry platinum wires are the material of choice fior flame tests without contamination and one generates hydrogen with zinc and simple adds, not with mercury. [Pg.975]


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See also in sourсe #XX -- [ Pg.205 ]

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