Conversions formula weight

Unit conversion, formula weights, rate constants. 

Ans. There are 6.02 X 10 i atoms in 1.00 mol Na (Avogadro s number). There is 23.0 g of Na in LOO mol Na (equal to the atomic weight in grams). This problem requires use of two of the most important conversion factors involving moles. Note which one is used with masses and which one is used with numbers of atoms (or molecules of formula units). With numbers of atoms, molecules, or formula units, use Avogadro s number with mass or weight use the formula weight. 

Note Because there is a constant conversion factor between grams and pounds, we can work totally in pounds. Since the formula weights are CuFeS2 (183.5 g/mol), Cu2S (159.2 g/mol) and Cu (63.55 g/mol), we have... 

Chain transfer constant, Ca° Reversible transfer constant, Ca Intrinsic molecular weight, Mn° Formula weight of monomer, Fwm Monomer/precatalyst ratio, Meq CTA/precatalyst ratio, Aeq Monomer conversion, X,... 

Ozone Concentrations Cc(wtf cjvol.) Weight % Volume % Co g m"3 Conversion Formula... 

This is done by first calculating the concentration of boric acid via the boron to chlorinity ratio of Culkin (21) and a general salinity-molecular weight conversion formula... 

Conversion from moles to grams, and vice versa, requires only the formula weight of the compound of interest. Consider the following examples. 

What does 1 ppm represent in terms of moles per liter It depends on the formula weight, but the approximate relationship between concentrations in parts per million (or parts per billion) and in moles per liter can be seen by assuming a formula weight of 100 for an analyte. Then, since 1 ppm = 10 g/L, it is equal to (10 g/L) (10 g/mol) = 10 mol/L. Similarly, 1 ppb = 10 mol/L. Note that this latter concentration is smaller than the hydrogen ion concentration in pure water (10" mol/L) Of course, this relationship is approximate and will vary with the formula weight. One part per million solutions of zinc and copper, for example, will not be the same molarity. Conversely, equal molar solutions of different species will not be equal in terms of ppm unless the formula weights are equal. The former concentration is based on the number of molecules per unit volume, while the latter is based on the weight of the species per unit volume. 

For the conversion of weight % to mole %in ternary mixtures Lessels [13] gives a useful nomogram. In the case of binary mixtures the various conversions are performed with the following formulae, which all refer to the low-boiling component 1. ... 

Notice that this conversion factor is the product of the three factors in Problem 4.34. It is another interpretation of the balanced equation which states that 1 formula weight of H3PO4 will produce 1 formula weight of Na3P04. 

Formula weight 175.93. Colorless crystals. M.p. 110°C (conversion to HlgOg) d (0°C) 4.629. Water is partially eliminated even at 70°C, especially if even a trace of HlOg-IgOg is present. Above 220°C, complete dehydration to IgOg occurs. 

Formula weight 187.44. Very slightly soluble in water, slowly reacts with dilute mineral acids. Corundum structure (D51 type). Heating at 600°C in air produces slow monotropic conversion to iS-GasOa. On heating in an autoclave under water vapor above 305°C converts to /S-GaaOg, below305°C, to GaO(OH) (see above), d 6.44. 

Solve Because the calcium ion is Ca and the nitrate ion is NOa, calcium nitrate is Ca(N03)2. Adding the atomic weights of the elements in the compound gives a formula weight of 164.1 amu. Using 1 molCa(N03)2 = 164.1 gCa(N03)2 to write the appropriate conversion factor, we have... 

The common way to characterize the composition of sodium silicates is to use the ratio of silica to alkali by weight. The first refers to the Si02 content of the materiaL and the latter to its NajO content. This characteristic value is often called modulus. The ratio between silicon dioxide and sodium oxide can also be expressed on a molar basis. The conversion of modulus and molar ratio is possible by the respective formula weights. In case of sodium silicates, the modulus has to be multiplied by a conversion factor of 1.032 to obtain the molar ratio [1,5,6-13]. 

Use the formula weight to write the factor that converts from mol ZnU to g Znl2. Note that the unit you are converting from (mol Znl2> is on the bottom of the conversion factor, and the unit you are converting to (g Znl2> is on the top. 

This is a gram-to-mole conversion. Grams of KCIO3 must be converted to moles before we can use the mole ratio from the equation to get moles of oxygen. The formula weight of KCIO3 is 122.548 g/mol. 

This is a gram-to-gram conversion Given 0.500 grams of Al, how many grams of AljOj can form Thus the three steps are needed. The formula weight of AljOj is 101.961 g/mol. 

If Va is the volume of gas A in cubic centimeters at t°C and Pa, Ma is the gram-mole volume of A decided upon, expressed as cubic centimeters, ds is the density of the liquid S used to absorb the gas, and Mg is the molecular weight of S (taken as the formula weight), then the mole ratio Xa is given by Va and Na then equals Xa/(1 + Xa). The Xa value relates to the temperature and pressure of measurement and to the gram-mole volume chosen for these conditions. For arguments on a molecular basis, I can find no useful purpose in the conversion of the Ostwald coefficient into the Bunsen coefficient. 

Formulas, Molecular and Equivalent Weights, and Conversion Factors to CaCO, of Substances Frequently Appearing in the Chemistry of Water Softening... 

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