Chlorine atomic weight

This, the mass per unit volume, is a function of the weight of individual molecules and the way they pack. The hydrocarbons do not possess heavy atoms and therefore the mass of the molecule per unit volume is rather low. Amorphous hydrocarbon polymers generally have specific gravities of 0.86-1.05. Where large atoms are present, e.g. chlorine atoms, the mass per unit volume is higher and so PVC, a substantially amorphous polymer, has a specific gravity of about 1.4. 

Pure sodium chloride, like pure water, has a definite melting (freezing) temperature (at a given pressure). Separating operations—such as distilling or freezing—do not separate the salt into components. The composition of the salt, whether expressed in relative numbers of sodium and chlorine atoms or in the relative weights of these atoms, is fixed and is represented by the formula NaCl. Sodium chloride, like water, is an example of a pure substance. 

How much would 0.754 mole of chlorine-35 atoms weigh How much would 0.246 mole of chlorine-37 atoms weigh What is the weight of a mole of average atoms in a mixture of the above samples What is the atomic weight of the naturally occurring mixture of these two isotopes of chlorine ... 

The presence of three chlorine atoms is easily determined by the isotope ratios. The odd molecular weight shows the presence of nitrogen. The loss of m/z 30 and 46 from the molecular ions shows the presence of the nitro group. 

Some simple global descriptors are molecular weight, number of atoms present in a molecule (e.g., number of chlorine atoms), number of double bonds, etc. Other descriptors represent the ramification of the molecule. Certain descriptors take into consideration the electronic charge on a certain atom, or its polarity. 

EXAMPLE 18.15. If 6.90g of an element, X, combines with 35.5g of chlorine, docs the element have atomic weight 6.90 and a chloride of formula XCl or does it have atomic weight 13.8 and a chloride with formula XC12 ... 

The weight of chlorine in the solid product can be determined by taking the weight of chlorine in the original compound (which has all of the chlorine atoms in it) and multiplying it by the percent of chlorine found in the solid product. This becomes 1.17 grams of chlorine x 0.334 = 0.391 g chlorine in the solid product. 

The value 70.9 is the molecular weight (mass) of the diatomic chlorine obtained by multiplying the atomic weight of chlorine (from the periodic table) by two. 

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