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Energy change in free

Here G is the free energy and AG the change in free energy during the reaction. R the gas constant and T the absolute temperature. [Pg.66]

Fig. 5. To generate an ensemble using Molecular Dynamics or Monte-Carlo simulation techniques the interaction between all pairs of atoms within a given cutoff radius must be considered. In contrast, to estimate changes in free energy using a stored trajectory only those interactions which are perturbed need be determined making the approach highly efficient. Fig. 5. To generate an ensemble using Molecular Dynamics or Monte-Carlo simulation techniques the interaction between all pairs of atoms within a given cutoff radius must be considered. In contrast, to estimate changes in free energy using a stored trajectory only those interactions which are perturbed need be determined making the approach highly efficient.
Table 3. Conformational free energy simulation of linear DPDPE. Changes in free energy and its components. Units kcal/mol... Table 3. Conformational free energy simulation of linear DPDPE. Changes in free energy and its components. Units kcal/mol...
Practical Solubility Concepts. Solution theory can provide a convenient, effective framework for solvent selection and blend formulation (3). When a solute dissolves in a solvent, a change in free energy occurs as a result of solvent—solute interactions. The change in free energy of mixing must be negative for dissolution to occur. In equation 1,... [Pg.264]

Classical thermodynamics gives an expression that relates the equilibrium constant (the distribution coefficient (K)) to the change in free energy of a solute when transferring from one phase to the other. The derivation of this relationship is fairly straightforward, but will not be given here, as it is well explained in virtually all books on classical physical chemistry [1,2]. [Pg.47]

Let us apply this method to the hypothetical reaction coordinate diagram of Fig. 5-11, which consists of two sections. The requisite energy differences are for the vertical distances (T2 — R) and (T3 — I2). Because (T3 — I2) > (T2 — R), the second section contains the rds, which must be the I2 —> T3 step. Note that T3 actually has a lower free energy than do Ti and T2 it is the change in free energy from the valley at the beginning of the section that determines the rate. [Pg.214]

It also follows that, when three (or more) oxidation states lie approximately on a straight line in the volt-equivalent diagram, they tend to form an equilibrium mixture rather than a reaction going to completion (provided that the attainment of thermodynamic equilibrium is not hindered kinetically). This is because the slopes joining the several points are almost the same, so that E° for the various couples (and hence AG°) are the same there is consequently approximately zero change in free energy and a balanced... [Pg.436]

It should be noted that the transformation of A into B by the A variable may or may not correspond to a physically realizable transformation. The change in free energy between two neighbouring points is then given analogously to (16.21), and the whole change is a sum over such terms. [Pg.381]

Other thermodynamic functions described above in that the change in free energy AG is determined solely by the initial and final states of the system. The maximum work, or maximum available energy, defined in terms of the Gibbs free energy G, which is now called the free enthalpy, is... [Pg.1225]

The relationship between the change in free energy AG and the equilibrium constant K is given by the vant Hofif isotherm... [Pg.1230]

In any process the change in entropy is, of course, equal to the temperature coefficient of the change in free energy, taken with opposite sign ... [Pg.101]

The Conventional Standard Free Energy of Solution. Returning now to the solution of a crystalline solid, let us consider the free energy of solution. Taking a uni-univalent substance let AF denote the change in free energy per mole when additional ions are added to a solution at temperature T where the solute has the mole fraction x and let us fix attention on the quantity... [Pg.106]

Two Cells Placed Back to Back. In Sec. 57 of Chapter 6 we discussed the e.m.f. of two cells placed back to back. Both cells contained the same solute in aqueous solution, but at different concentrations. We saw that, when a current flows, the net result is simply to transfer an amount of solute from one solution to the other. Hence the observed resultant e.m.f. of the pair of cells is a measure of the change in free energy on transferring a pair of ions from one solution to the other in fact, this change of free energy expressed in electron-volts is numerically equal to the e.m.f. expressed in volts. [Pg.220]

On closing the external circuit between the two Ag electrodes, when a current flows, the net result will be simply to transfer an amount of solute from one solvent to the other, and the measured e.m.f. will be equal to the change in free energy associated with the transfer of a kome of ions from one solvent to the other. This quantity will contain, in addition to the usual communal term, a unitary term arising from the fact that, in the co-sphere of each positive ion and each negative ion, the amount of free energy lost by the dipoles of one solvent will be different from that lost by the dipoles of the other solvent. [Pg.221]

We shall be interested in pairs of cells, in which the mole fraction of the solute in one solvent is equal to its mole fraction in the other solvent. Suppose then that a series of such pairs of cells is made up, with the solute at progressively greater dilutions. When the members of these pairs of cells are placed back to back, the resultant e.m.f. s will contain progressively smaller contributions from the intcrionic forces and, on extrapolation to extreme dilution, this contribution will be negligibly small. Since the mole fraction on each side is the same, the difference between the eratic terms will be zero. In any such scries of cells, the measured e.m.f. s when extrapolated to extreme dilution thus yield the unitary part of the change in free energy. [Pg.221]


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See also in sourсe #XX -- [ Pg.173 ]




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