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Oxygen-boron bonds nitrogen hydrides

The element before carbon in Period 2, boron, has one electron less than carbon, and forms many covalent compounds of type BX3 where X is a monovalent atom or group. In these, the boron uses three sp hybrid orbitals to form three trigonal planar bonds, like carbon in ethene, but the unhybridised 2p orbital is vacant, i.e. it contains no electrons. In the nitrogen atom (one more electron than carbon) one orbital must contain two electrons—the lone pair hence sp hybridisation will give four tetrahedral orbitals, one containing this lone pair. Oxygen similarly hybridised will have two orbitals occupied by lone pairs, and fluorine, three. Hence the hydrides of the elements from carbon to fluorine have the structures... [Pg.57]


See other pages where Oxygen-boron bonds nitrogen hydrides is mentioned: [Pg.26]    [Pg.159]    [Pg.1619]    [Pg.154]    [Pg.154]    [Pg.1618]    [Pg.941]    [Pg.74]    [Pg.439]    [Pg.205]    [Pg.195]   
See also in sourсe #XX -- [ Pg.4 , Pg.4 , Pg.4 , Pg.5 , Pg.5 , Pg.7 , Pg.7 ]




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Boron bonding

Boron oxygen bonds

Boron-nitrogen bonds

Boron-oxygen

Nitrogen hydrides

Nitrogen-oxygen bonds

Oxygen hydrides

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