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Vibronic couplings through totally symmetric modes

A term. One excited electronic state e is included in this term. With vq approaching Vg the Raman line associated with a totally symmetric mode derives its intensity from this term through the Franck-Condon mechanism. This term does not depend on vibronic mixing of state e with odier electronic states of the molecule. If the two electronic states g and e lie far below the next electronic levels and, hence, the probability of vibronic coupling between state e and the other excited electronic states is very low, the A term dominates in magnitude over the other two terms in Eq. (8.68). [Pg.209]


See other pages where Vibronic couplings through totally symmetric modes is mentioned: [Pg.27]    [Pg.180]    [Pg.435]    [Pg.7]    [Pg.236]    [Pg.91]    [Pg.102]    [Pg.337]    [Pg.144]    [Pg.7]    [Pg.210]   
See also in sourсe #XX -- [ Pg.47 , Pg.48 , Pg.49 , Pg.50 , Pg.51 , Pg.52 , Pg.53 , Pg.54 , Pg.55 , Pg.56 ]




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Coupled modes

Mode coupling

Totally Symmetric Modes

Totally symmetric

Vibron

Vibronic coupling

Vibronic modes

Vibronics

Vibrons

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