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THERMODYNAMICS THE SECOND AND THIRD LAWS

Upon integration, this gives A5 = n Cp In 7. The answer is calculated by [Pg.211]

7 Assume the process is isothermal and reversible and use the relationship d5 =. Because the process is isothermal, At/ = 0 and hence q - -vr, where w - -PdK. Making this substitution, we obtain [Pg.212]

13 Assume the transfer of energy as heat is reversible. The change in entropy [Pg.213]

For the transfer of heat from block 2 to block 1 to be spontaneous, AS must be positive and. therefore, Tj would have to be greater than Tj. [Pg.213]

15 (a) Heat enters house interior and entropy of the house interior increases. [Pg.213]

See other pages where THERMODYNAMICS THE SECOND AND THIRD LAWS is mentioned: [Pg.386]    [Pg.389]    [Pg.391]    [Pg.393]    [Pg.395]    [Pg.399]    [Pg.403]    [Pg.407]    [Pg.409]    [Pg.413]    [Pg.415]    [Pg.417]    [Pg.421]    [Pg.423]    [Pg.427]    [Pg.429]    [Pg.13]    [Pg.449]    [Pg.451]    [Pg.453]    [Pg.455]    [Pg.457]    [Pg.459]    [Pg.461]    [Pg.463]    [Pg.465]    [Pg.467]    [Pg.469]    [Pg.471]    [Pg.473]    [Pg.475]    [Pg.477]    [Pg.479]    [Pg.481]    [Pg.483]    [Pg.485]    [Pg.487]    [Pg.489]    [Pg.446]    [Pg.211]    [Pg.112]    [Pg.113]    [Pg.114]    [Pg.115]    [Pg.116]   


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